Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 278 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 56000 people. The population grows by 5% every year. What will the population be after 3 years?
2. 2.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
3. 3.What amount will ₹54800 grow to in 2 years at 25% per year compound interest (in ₹)?
4. 4.What amount will ₹27500 grow to in 2 years at 12% per year compound interest (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹2800 at 5% per year for 2 years (in ₹)?
6. 6.What amount will ₹56800 grow to in 2 years at 15% per year compound interest (in ₹)?
7. 7.What amount will ₹28500 grow to in 1 year at 20% per year compound interest (in ₹)?
8. 8.Find the compound interest on ₹24100 at 10% per year for 2 years, compounded every year (in ₹).
9. 9.What is the difference between the compound interest and the simple interest on ₹60000 at 4% per year for 2 years (in ₹)?
10. 10.A scooter is worth ₹55000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
11. 11.What amount will ₹56200 grow to in 1 year at 20% per year compound interest (in ₹)?
12. 12.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
13. 13.A scooter is worth ₹20000. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
14. 14.A scooter is worth ₹2500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
15. 15.Find the compound interest on ₹42400 at 8% per year for 1 year, compounded every year (in ₹).
16. 16.What is the difference between the compound interest and the simple interest on ₹50000 at 8% per year for 2 years (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
18. 18.Find the compound interest on ₹18200 at 8% per year for 1 year, compounded every year (in ₹).
19. 19.What amount will ₹32500 grow to in 2 years at 4% per year compound interest (in ₹)?
20. 20.What amount will ₹28300 grow to in 1 year at 25% per year compound interest (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹27500 at 8% per year for 2 years (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹9700 at 10% per year for 2 years (in ₹)?
23. 23.A town has 18500 people. The population grows by 5% every year. What will the population be after 1 year?
24. 24.A town has 10000 people. The population grows by 10% every year. What will the population be after 3 years?
25. 25.Find the compound interest on ₹11200 at 25% per year for 3 years, compounded every year (in ₹).
26. 26.Find the compound interest on ₹35000 at 8% per year for 2 years, compounded every year (in ₹).
27. 27.A town has 30900 people. The population grows by 5% every year. What will the population be after 1 year?
28. 28.Find the compound interest on ₹55300 at 10% per year for 2 years, compounded every year (in ₹).
29. 29.What amount will ₹25000 grow to in 2 years at 8% per year compound interest (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
31. 31.A scooter is worth ₹6900. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹16600 at 10% per year for 2 years (in ₹)?
33. 33.Find the compound interest on ₹37000 at 10% per year for 3 years, compounded every year (in ₹).
34. 34.What is the difference between the compound interest and the simple interest on ₹7600 at 5% per year for 2 years (in ₹)?
35. 35.A scooter is worth ₹8400. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
36. 36.What amount will ₹36200 grow to in 1 year at 12% per year compound interest (in ₹)?
37. 37.Find the compound interest on ₹3900 at 4% per year for 1 year, compounded every year (in ₹).
38. 38.Find the compound interest on ₹29500 at 25% per year for 1 year, compounded every year (in ₹).
39. 39.A town has 20000 people. The population grows by 8% every year. What will the population be after 2 years?
40. 40.A scooter is worth ₹42500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets