Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 281 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹17000 at 10% per year for 1 year, compounded every year (in ₹).
2. 2.Find the compound interest on ₹33600 at 25% per year for 3 years, compounded every year (in ₹).
3. 3.What is the difference between the compound interest and the simple interest on ₹55200 at 5% per year for 2 years (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹57500 at 12% per year for 2 years (in ₹)?
5. 5.Find the compound interest on ₹55000 at 4% per year for 2 years, compounded every year (in ₹).
6. 6.What is the difference between the compound interest and the simple interest on ₹21700 at 10% per year for 2 years (in ₹)?
7. 7.A town has 24000 people. The population grows by 10% every year. What will the population be after 2 years?
8. 8.Find the compound interest on ₹42000 at 20% per year for 3 years, compounded every year (in ₹).
9. 9.What amount will ₹7200 grow to in 1 year at 25% per year compound interest (in ₹)?
10. 10.A town has 52100 people. The population grows by 15% every year. What will the population be after 1 year?
11. 11.What amount will ₹8400 grow to in 1 year at 4% per year compound interest (in ₹)?
12. 12.What amount will ₹17600 grow to in 3 years at 25% per year compound interest (in ₹)?
13. 13.What amount will ₹14400 grow to in 3 years at 25% per year compound interest (in ₹)?
14. 14.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
15. 15.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
16. 16.What amount will ₹8000 grow to in 1 year at 25% per year compound interest (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?
18. 18.A scooter is worth ₹55900. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
20. 20.A scooter is worth ₹56000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
21. 21.What amount will ₹13000 grow to in 3 years at 10% per year compound interest (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹50000 at 5% per year for 2 years (in ₹)?
23. 23.A town has 16300 people. The population grows by 8% every year. What will the population be after 1 year?
24. 24.A town has 6900 people. The population grows by 8% every year. What will the population be after 1 year?
25. 25.What is the difference between the compound interest and the simple interest on ₹16000 at 5% per year for 2 years (in ₹)?
26. 26.A town has 8600 people. The population grows by 20% every year. What will the population be after 2 years?
27. 27.Find the compound interest on ₹18000 at 10% per year for 3 years, compounded every year (in ₹).
28. 28.Find the compound interest on ₹52500 at 8% per year for 2 years, compounded every year (in ₹).
29. 29.What is the difference between the compound interest and the simple interest on ₹49000 at 10% per year for 2 years (in ₹)?
30. 30.Find the compound interest on ₹57400 at 10% per year for 1 year, compounded every year (in ₹).
31. 31.Find the compound interest on ₹8800 at 8% per year for 1 year, compounded every year (in ₹).
32. 32.Find the compound interest on ₹57600 at 20% per year for 1 year, compounded every year (in ₹).
33. 33.Find the compound interest on ₹7500 at 12% per year for 2 years, compounded every year (in ₹).
34. 34.What is the difference between the compound interest and the simple interest on ₹7200 at 5% per year for 2 years (in ₹)?
35. 35.Find the compound interest on ₹59400 at 8% per year for 1 year, compounded every year (in ₹).
36. 36.A town has 48000 people. The population grows by 25% every year. What will the population be after 3 years?
37. 37.A town has 52800 people. The population grows by 25% every year. What will the population be after 3 years?
38. 38.What amount will ₹30000 grow to in 2 years at 25% per year compound interest (in ₹)?
39. 39.What amount will ₹23000 grow to in 3 years at 10% per year compound interest (in ₹)?
40. 40.A scooter is worth ₹28800. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets