Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 283 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 36300 people. The population grows by 25% every year. What will the population be after 1 year?
2. 2.What amount will ₹41200 grow to in 1 year at 5% per year compound interest (in ₹)?
3. 3.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
4. 4.What is the difference between the compound interest and the simple interest on ₹50800 at 25% per year for 2 years (in ₹)?
5. 5.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
6. 6.What amount will ₹27500 grow to in 2 years at 8% per year compound interest (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹19600 at 5% per year for 2 years (in ₹)?
8. 8.What amount will ₹32000 grow to in 3 years at 5% per year compound interest (in ₹)?
9. 9.A scooter is worth ₹56000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
10. 10.Find the compound interest on ₹32400 at 15% per year for 2 years, compounded every year (in ₹).
11. 11.A town has 8600 people. The population grows by 20% every year. What will the population be after 1 year?
12. 12.A town has 31000 people. The population grows by 10% every year. What will the population be after 2 years?
13. 13.A town has 32500 people. The population grows by 4% every year. What will the population be after 2 years?
14. 14.Find the compound interest on ₹46500 at 15% per year for 1 year, compounded every year (in ₹).
15. 15.What is the difference between the compound interest and the simple interest on ₹17500 at 12% per year for 2 years (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹33600 at 10% per year for 2 years (in ₹)?
17. 17.Find the compound interest on ₹5100 at 20% per year for 1 year, compounded every year (in ₹).
18. 18.A town has 24100 people. The population grows by 15% every year. What will the population be after 1 year?
19. 19.Find the compound interest on ₹27500 at 12% per year for 2 years, compounded every year (in ₹).
20. 20.What amount will ₹15000 grow to in 2 years at 20% per year compound interest (in ₹)?
21. 21.Find the compound interest on ₹55000 at 4% per year for 2 years, compounded every year (in ₹).
22. 22.What amount will ₹32500 grow to in 2 years at 4% per year compound interest (in ₹)?
23. 23.A scooter is worth ₹54900. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
24. 24.Find the compound interest on ₹7600 at 25% per year for 2 years, compounded every year (in ₹).
25. 25.What is the difference between the compound interest and the simple interest on ₹20000 at 4% per year for 2 years (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
27. 27.Find the compound interest on ₹19200 at 25% per year for 3 years, compounded every year (in ₹).
28. 28.What is the difference between the compound interest and the simple interest on ₹52500 at 4% per year for 2 years (in ₹)?
29. 29.A town has 57600 people. The population grows by 25% every year. What will the population be after 3 years?
30. 30.Find the compound interest on ₹24400 at 15% per year for 1 year, compounded every year (in ₹).
31. 31.What amount will ₹17600 grow to in 1 year at 12% per year compound interest (in ₹)?
32. 32.A town has 55000 people. The population grows by 8% every year. What will the population be after 2 years?
33. 33.What is the difference between the compound interest and the simple interest on ₹9200 at 5% per year for 2 years (in ₹)?
34. 34.What amount will ₹43200 grow to in 2 years at 5% per year compound interest (in ₹)?
35. 35.Find the compound interest on ₹37300 at 10% per year for 1 year, compounded every year (in ₹).
36. 36.A town has 30000 people. The population grows by 8% every year. What will the population be after 2 years?
37. 37.A town has 47700 people. The population grows by 20% every year. What will the population be after 1 year?
38. 38.Find the compound interest on ₹43000 at 25% per year for 1 year, compounded every year (in ₹).
39. 39.Find the compound interest on ₹53200 at 20% per year for 1 year, compounded every year (in ₹).
40. 40.What amount will ₹6500 grow to in 2 years at 20% per year compound interest (in ₹)?

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