Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 286 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹4000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
2. 2.Find the compound interest on ₹21200 at 20% per year for 2 years, compounded every year (in ₹).
3. 3.A town has 42400 people. The population grows by 25% every year. What will the population be after 1 year?
4. 4.Find the compound interest on ₹17200 at 10% per year for 2 years, compounded every year (in ₹).
5. 5.Find the compound interest on ₹9600 at 4% per year for 1 year, compounded every year (in ₹).
6. 6.Find the compound interest on ₹35300 at 8% per year for 1 year, compounded every year (in ₹).
7. 7.Find the compound interest on ₹43600 at 10% per year for 2 years, compounded every year (in ₹).
8. 8.A town has 47800 people. The population grows by 25% every year. What will the population be after 1 year?
9. 9.What is the difference between the compound interest and the simple interest on ₹11600 at 5% per year for 2 years (in ₹)?
10. 10.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
11. 11.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
12. 12.A town has 24000 people. The population grows by 4% every year. What will the population be after 1 year?
13. 13.What is the difference between the compound interest and the simple interest on ₹43600 at 10% per year for 2 years (in ₹)?
14. 14.A scooter is worth ₹42000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
15. 15.Find the compound interest on ₹9900 at 20% per year for 2 years, compounded every year (in ₹).
16. 16.Find the compound interest on ₹47400 at 10% per year for 2 years, compounded every year (in ₹).
17. 17.What amount will ₹38500 grow to in 2 years at 20% per year compound interest (in ₹)?
18. 18.Find the compound interest on ₹18900 at 20% per year for 2 years, compounded every year (in ₹).
19. 19.What amount will ₹7400 grow to in 1 year at 8% per year compound interest (in ₹)?
20. 20.A scooter is worth ₹31200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
21. 21.Find the compound interest on ₹29800 at 10% per year for 2 years, compounded every year (in ₹).
22. 22.What amount will ₹46700 grow to in 1 year at 12% per year compound interest (in ₹)?
23. 23.A town has 32500 people. The population grows by 10% every year. What will the population be after 1 year?
24. 24.A town has 33800 people. The population grows by 20% every year. What will the population be after 1 year?
25. 25.What is the difference between the compound interest and the simple interest on ₹11100 at 10% per year for 2 years (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹24800 at 5% per year for 2 years (in ₹)?
28. 28.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
29. 29.Find the compound interest on ₹42800 at 20% per year for 1 year, compounded every year (in ₹).
30. 30.What is the difference between the compound interest and the simple interest on ₹5000 at 10% per year for 2 years (in ₹)?
31. 31.Find the compound interest on ₹52200 at 12% per year for 1 year, compounded every year (in ₹).
32. 32.What is the difference between the compound interest and the simple interest on ₹22500 at 8% per year for 2 years (in ₹)?
33. 33.A scooter is worth ₹53900. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
34. 34.What amount will ₹17500 grow to in 3 years at 20% per year compound interest (in ₹)?
35. 35.What is the difference between the compound interest and the simple interest on ₹22500 at 12% per year for 2 years (in ₹)?
36. 36.What amount will ₹56000 grow to in 3 years at 15% per year compound interest (in ₹)?
37. 37.A scooter is worth ₹20800. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
38. 38.What is the difference between the compound interest and the simple interest on ₹42000 at 5% per year for 2 years (in ₹)?
39. 39.Find the compound interest on ₹12500 at 8% per year for 2 years, compounded every year (in ₹).
40. 40.What amount will ₹4000 grow to in 3 years at 10% per year compound interest (in ₹)?

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