Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
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- 1.What amount will ₹52000 grow to in 2 years at 10% per year compound interest (in ₹)?
- 2.A scooter is worth ₹13100. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 3.What is the difference between the compound interest and the simple interest on ₹12500 at 8% per year for 2 years (in ₹)?
- 4.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
- 5.A scooter is worth ₹11000. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 6.Find the compound interest on ₹35000 at 12% per year for 2 years, compounded every year (in ₹).
- 7.A town has 30400 people. The population grows by 25% every year. What will the population be after 2 years?
- 8.A scooter is worth ₹26000. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 9.What amount will ₹52500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 10.Find the compound interest on ₹52000 at 15% per year for 2 years, compounded every year (in ₹).
- 11.Find the compound interest on ₹27200 at 25% per year for 3 years, compounded every year (in ₹).
- 12.A scooter is worth ₹25000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 13.Find the compound interest on ₹40000 at 8% per year for 2 years, compounded every year (in ₹).
- 14.What is the difference between the compound interest and the simple interest on ₹47500 at 4% per year for 2 years (in ₹)?
- 15.Find the compound interest on ₹56000 at 5% per year for 1 year, compounded every year (in ₹).
- 16.A scooter is worth ₹44300. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
- 17.What is the difference between the compound interest and the simple interest on ₹58000 at 15% per year for 2 years (in ₹)?
- 18.Find the compound interest on ₹2500 at 8% per year for 2 years, compounded every year (in ₹).
- 19.What amount will ₹20700 grow to in 1 year at 12% per year compound interest (in ₹)?
- 20.A town has 20000 people. The population grows by 8% every year. What will the population be after 2 years?
- 21.What amount will ₹46800 grow to in 2 years at 15% per year compound interest (in ₹)?
- 22.A scooter is worth ₹47600. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 23.A town has 47200 people. The population grows by 5% every year. What will the population be after 2 years?
- 24.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
- 25.What amount will ₹16000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 26.Find the compound interest on ₹40000 at 4% per year for 2 years, compounded every year (in ₹).
- 27.Find the compound interest on ₹28500 at 20% per year for 3 years, compounded every year (in ₹).
- 28.A town has 10000 people. The population grows by 5% every year. What will the population be after 2 years?
- 29.A town has 30400 people. The population grows by 10% every year. What will the population be after 1 year?
- 30.A scooter is worth ₹32500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 31.What amount will ₹37200 grow to in 2 years at 20% per year compound interest (in ₹)?
- 32.A town has 16500 people. The population grows by 20% every year. What will the population be after 2 years?
- 33.What amount will ₹47600 grow to in 2 years at 5% per year compound interest (in ₹)?
- 34.A town has 27200 people. The population grows by 25% every year. What will the population be after 3 years?
- 35.A scooter is worth ₹5000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 36.What is the difference between the compound interest and the simple interest on ₹16400 at 15% per year for 2 years (in ₹)?
- 37.Find the compound interest on ₹5200 at 15% per year for 2 years, compounded every year (in ₹).
- 38.What is the difference between the compound interest and the simple interest on ₹17700 at 10% per year for 2 years (in ₹)?
- 39.A town has 15000 people. The population grows by 4% every year. What will the population be after 2 years?
- 40.What amount will ₹27200 grow to in 2 years at 20% per year compound interest (in ₹)?
Answer key
- 62920
- 12052
- 80
- 3783
- 9350
- 8904
- 47500
- 23400
- 56784
- 16770
- 25925
- 21160
- 6656
- 76
- 2800
- 38984
- 1305
- 416
- 23184
- 23328
- 61893
- 26775
- 52038
- 20835
- 21296
- 3264
- 20748
- 11025
- 33440
- 25168
- 53568
- 23760
- 52479
- 53125
- 3645
- 369
- 1677
- 177
- 16224
- 39168
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