Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 29 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹35500 at 20% per year for 3 years, compounded every year (in ₹).
2. 2.Find the compound interest on ₹22700 at 15% per year for 1 year, compounded every year (in ₹).
3. 3.A town has 7000 people. The population grows by 10% every year. What will the population be after 3 years?
4. 4.Find the compound interest on ₹21000 at 20% per year for 3 years, compounded every year (in ₹).
5. 5.What is the difference between the compound interest and the simple interest on ₹20000 at 12% per year for 2 years (in ₹)?
6. 6.A town has 27200 people. The population grows by 5% every year. What will the population be after 2 years?
7. 7.What amount will ₹19800 grow to in 1 year at 12% per year compound interest (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹56000 at 10% per year for 2 years (in ₹)?
9. 9.Find the compound interest on ₹3200 at 5% per year for 2 years, compounded every year (in ₹).
10. 10.Find the compound interest on ₹12500 at 4% per year for 2 years, compounded every year (in ₹).
11. 11.What amount will ₹38500 grow to in 3 years at 20% per year compound interest (in ₹)?
12. 12.A scooter is worth ₹12500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹40000 at 4% per year for 2 years (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹47500 at 4% per year for 2 years (in ₹)?
15. 15.Find the compound interest on ₹29000 at 20% per year for 3 years, compounded every year (in ₹).
16. 16.Find the compound interest on ₹6400 at 5% per year for 2 years, compounded every year (in ₹).
17. 17.What is the difference between the compound interest and the simple interest on ₹24800 at 5% per year for 2 years (in ₹)?
18. 18.A scooter is worth ₹48300. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
19. 19.Find the compound interest on ₹28000 at 10% per year for 1 year, compounded every year (in ₹).
20. 20.A scooter is worth ₹8000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹22500 at 12% per year for 2 years (in ₹)?
22. 22.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
23. 23.Find the compound interest on ₹8100 at 4% per year for 1 year, compounded every year (in ₹).
24. 24.A town has 41700 people. The population grows by 10% every year. What will the population be after 1 year?
25. 25.A town has 56700 people. The population grows by 5% every year. What will the population be after 1 year?
26. 26.A town has 31500 people. The population grows by 5% every year. What will the population be after 1 year?
27. 27.What amount will ₹22400 grow to in 1 year at 5% per year compound interest (in ₹)?
28. 28.A scooter is worth ₹6000. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
29. 29.Find the compound interest on ₹5200 at 25% per year for 2 years, compounded every year (in ₹).
30. 30.A town has 22600 people. The population grows by 20% every year. What will the population be after 2 years?
31. 31.What is the difference between the compound interest and the simple interest on ₹43100 at 10% per year for 2 years (in ₹)?
32. 32.A town has 26000 people. The population grows by 10% every year. What will the population be after 3 years?
33. 33.Find the compound interest on ₹13400 at 20% per year for 2 years, compounded every year (in ₹).
34. 34.What amount will ₹2000 grow to in 1 year at 15% per year compound interest (in ₹)?
35. 35.Find the compound interest on ₹7500 at 12% per year for 2 years, compounded every year (in ₹).
36. 36.A scooter is worth ₹37500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
37. 37.A town has 25000 people. The population grows by 8% every year. What will the population be after 2 years?
38. 38.What amount will ₹22000 grow to in 2 years at 5% per year compound interest (in ₹)?
39. 39.Find the compound interest on ₹29300 at 15% per year for 1 year, compounded every year (in ₹).
40. 40.What amount will ₹12500 grow to in 3 years at 20% per year compound interest (in ₹)?

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