Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
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- 1.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
- 2.Find the compound interest on ₹13600 at 5% per year for 2 years, compounded every year (in ₹).
- 3.What amount will ₹6000 grow to in 2 years at 5% per year compound interest (in ₹)?
- 4.What amount will ₹46000 grow to in 2 years at 15% per year compound interest (in ₹)?
- 5.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 6.A scooter is worth ₹54100. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 7.A town has 37500 people. The population grows by 12% every year. What will the population be after 1 year?
- 8.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
- 9.Find the compound interest on ₹21300 at 12% per year for 1 year, compounded every year (in ₹).
- 10.Find the compound interest on ₹47500 at 8% per year for 2 years, compounded every year (in ₹).
- 11.What is the difference between the compound interest and the simple interest on ₹57600 at 5% per year for 2 years (in ₹)?
- 12.A town has 10000 people. The population grows by 8% every year. What will the population be after 2 years?
- 13.What is the difference between the compound interest and the simple interest on ₹39400 at 10% per year for 2 years (in ₹)?
- 14.A scooter is worth ₹10800. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
- 15.A town has 40500 people. The population grows by 20% every year. What will the population be after 2 years?
- 16.A town has 35400 people. The population grows by 4% every year. What will the population be after 1 year?
- 17.Find the compound interest on ₹41600 at 25% per year for 3 years, compounded every year (in ₹).
- 18.Find the compound interest on ₹5000 at 10% per year for 3 years, compounded every year (in ₹).
- 19.A town has 8000 people. The population grows by 15% every year. What will the population be after 3 years?
- 20.What is the difference between the compound interest and the simple interest on ₹5000 at 4% per year for 2 years (in ₹)?
- 21.What amount will ₹27200 grow to in 1 year at 10% per year compound interest (in ₹)?
- 22.What is the difference between the compound interest and the simple interest on ₹47500 at 8% per year for 2 years (in ₹)?
- 23.A town has 45000 people. The population grows by 8% every year. What will the population be after 2 years?
- 24.A scooter is worth ₹21200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 25.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
- 26.A scooter is worth ₹17400. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
- 27.Find the compound interest on ₹26000 at 10% per year for 3 years, compounded every year (in ₹).
- 28.A town has 8400 people. The population grows by 8% every year. What will the population be after 1 year?
- 29.Find the compound interest on ₹43600 at 5% per year for 2 years, compounded every year (in ₹).
- 30.What amount will ₹40000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 31.What is the difference between the compound interest and the simple interest on ₹16200 at 20% per year for 2 years (in ₹)?
- 32.Find the compound interest on ₹45600 at 25% per year for 2 years, compounded every year (in ₹).
- 33.Find the compound interest on ₹57300 at 25% per year for 1 year, compounded every year (in ₹).
- 34.A town has 48000 people. The population grows by 15% every year. What will the population be after 3 years?
- 35.What is the difference between the compound interest and the simple interest on ₹22500 at 12% per year for 2 years (in ₹)?
- 36.A scooter is worth ₹8000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 37.Find the compound interest on ₹14400 at 25% per year for 3 years, compounded every year (in ₹).
- 38.Find the compound interest on ₹40700 at 10% per year for 1 year, compounded every year (in ₹).
- 39.What amount will ₹7500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 40.What amount will ₹30000 grow to in 2 years at 12% per year compound interest (in ₹)?
Answer key
- 18522
- 1394
- 6615
- 60835
- 12167
- 43821
- 42000
- 3783
- 2556
- 7904
- 144
- 11664
- 394
- 8100
- 58320
- 36816
- 39650
- 1655
- 12167
- 8
- 29920
- 304
- 52488
- 19133
- 2522
- 13050
- 8606
- 9072
- 4469
- 43264
- 648
- 25650
- 14325
- 73002
- 324
- 6859
- 13725
- 4070
- 8748
- 37632
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