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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 291 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
  2. 2.Find the compound interest on ₹13600 at 5% per year for 2 years, compounded every year (in ₹).
  3. 3.What amount will ₹6000 grow to in 2 years at 5% per year compound interest (in ₹)?
  4. 4.What amount will ₹46000 grow to in 2 years at 15% per year compound interest (in ₹)?
  5. 5.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
  6. 6.A scooter is worth ₹54100. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  7. 7.A town has 37500 people. The population grows by 12% every year. What will the population be after 1 year?
  8. 8.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
  9. 9.Find the compound interest on ₹21300 at 12% per year for 1 year, compounded every year (in ₹).
  10. 10.Find the compound interest on ₹47500 at 8% per year for 2 years, compounded every year (in ₹).
  11. 11.What is the difference between the compound interest and the simple interest on ₹57600 at 5% per year for 2 years (in ₹)?
  12. 12.A town has 10000 people. The population grows by 8% every year. What will the population be after 2 years?
  13. 13.What is the difference between the compound interest and the simple interest on ₹39400 at 10% per year for 2 years (in ₹)?
  14. 14.A scooter is worth ₹10800. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  15. 15.A town has 40500 people. The population grows by 20% every year. What will the population be after 2 years?
  16. 16.A town has 35400 people. The population grows by 4% every year. What will the population be after 1 year?
  17. 17.Find the compound interest on ₹41600 at 25% per year for 3 years, compounded every year (in ₹).
  18. 18.Find the compound interest on ₹5000 at 10% per year for 3 years, compounded every year (in ₹).
  19. 19.A town has 8000 people. The population grows by 15% every year. What will the population be after 3 years?
  20. 20.What is the difference between the compound interest and the simple interest on ₹5000 at 4% per year for 2 years (in ₹)?
  21. 21.What amount will ₹27200 grow to in 1 year at 10% per year compound interest (in ₹)?
  22. 22.What is the difference between the compound interest and the simple interest on ₹47500 at 8% per year for 2 years (in ₹)?
  23. 23.A town has 45000 people. The population grows by 8% every year. What will the population be after 2 years?
  24. 24.A scooter is worth ₹21200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  25. 25.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
  26. 26.A scooter is worth ₹17400. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  27. 27.Find the compound interest on ₹26000 at 10% per year for 3 years, compounded every year (in ₹).
  28. 28.A town has 8400 people. The population grows by 8% every year. What will the population be after 1 year?
  29. 29.Find the compound interest on ₹43600 at 5% per year for 2 years, compounded every year (in ₹).
  30. 30.What amount will ₹40000 grow to in 2 years at 4% per year compound interest (in ₹)?
  31. 31.What is the difference between the compound interest and the simple interest on ₹16200 at 20% per year for 2 years (in ₹)?
  32. 32.Find the compound interest on ₹45600 at 25% per year for 2 years, compounded every year (in ₹).
  33. 33.Find the compound interest on ₹57300 at 25% per year for 1 year, compounded every year (in ₹).
  34. 34.A town has 48000 people. The population grows by 15% every year. What will the population be after 3 years?
  35. 35.What is the difference between the compound interest and the simple interest on ₹22500 at 12% per year for 2 years (in ₹)?
  36. 36.A scooter is worth ₹8000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  37. 37.Find the compound interest on ₹14400 at 25% per year for 3 years, compounded every year (in ₹).
  38. 38.Find the compound interest on ₹40700 at 10% per year for 1 year, compounded every year (in ₹).
  39. 39.What amount will ₹7500 grow to in 2 years at 8% per year compound interest (in ₹)?
  40. 40.What amount will ₹30000 grow to in 2 years at 12% per year compound interest (in ₹)?

Answer key

  1. 18522
  2. 1394
  3. 6615
  4. 60835
  5. 12167
  6. 43821
  7. 42000
  8. 3783
  9. 2556
  10. 7904
  11. 144
  12. 11664
  13. 394
  14. 8100
  15. 58320
  16. 36816
  17. 39650
  18. 1655
  19. 12167
  20. 8
  21. 29920
  22. 304
  23. 52488
  24. 19133
  25. 2522
  26. 13050
  27. 8606
  28. 9072
  29. 4469
  30. 43264
  31. 648
  32. 25650
  33. 14325
  34. 73002
  35. 324
  36. 6859
  37. 13725
  38. 4070
  39. 8748
  40. 37632

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