Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 294 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹52500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
2. 2.What amount will ₹40900 grow to in 2 years at 20% per year compound interest (in ₹)?
3. 3.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
4. 4.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
5. 5.What amount will ₹12400 grow to in 1 year at 10% per year compound interest (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹30800 at 25% per year for 2 years (in ₹)?
7. 7.A town has 39200 people. The population grows by 5% every year. What will the population be after 2 years?
8. 8.What is the difference between the compound interest and the simple interest on ₹39500 at 20% per year for 2 years (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹34400 at 5% per year for 2 years (in ₹)?
10. 10.Find the compound interest on ₹13600 at 5% per year for 2 years, compounded every year (in ₹).
11. 11.What amount will ₹57800 grow to in 1 year at 8% per year compound interest (in ₹)?
12. 12.A town has 50400 people. The population grows by 15% every year. What will the population be after 2 years?
13. 13.What amount will ₹28000 grow to in 3 years at 10% per year compound interest (in ₹)?
14. 14.What amount will ₹35600 grow to in 2 years at 5% per year compound interest (in ₹)?
15. 15.A town has 22000 people. The population grows by 20% every year. What will the population be after 3 years?
16. 16.A scooter is worth ₹58700. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
17. 17.Find the compound interest on ₹11700 at 20% per year for 2 years, compounded every year (in ₹).
18. 18.Find the compound interest on ₹14800 at 15% per year for 1 year, compounded every year (in ₹).
19. 19.Find the compound interest on ₹1600 at 25% per year for 3 years, compounded every year (in ₹).
20. 20.A scooter is worth ₹12100. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹36400 at 5% per year for 2 years (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹38800 at 25% per year for 2 years (in ₹)?
23. 23.What amount will ₹13600 grow to in 2 years at 25% per year compound interest (in ₹)?
24. 24.What amount will ₹5000 grow to in 2 years at 4% per year compound interest (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹57500 at 4% per year for 2 years (in ₹)?
26. 26.What amount will ₹22400 grow to in 2 years at 5% per year compound interest (in ₹)?
27. 27.A town has 56000 people. The population grows by 15% every year. What will the population be after 3 years?
28. 28.A town has 3200 people. The population grows by 15% every year. What will the population be after 2 years?
29. 29.A town has 16100 people. The population grows by 25% every year. What will the population be after 1 year?
30. 30.What is the difference between the compound interest and the simple interest on ₹42800 at 10% per year for 2 years (in ₹)?
31. 31.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
32. 32.Find the compound interest on ₹17600 at 25% per year for 3 years, compounded every year (in ₹).
33. 33.A town has 6400 people. The population grows by 10% every year. What will the population be after 2 years?
34. 34.What is the difference between the compound interest and the simple interest on ₹37600 at 25% per year for 2 years (in ₹)?
35. 35.What is the difference between the compound interest and the simple interest on ₹37600 at 15% per year for 2 years (in ₹)?
36. 36.A town has 3300 people. The population grows by 4% every year. What will the population be after 1 year?
37. 37.A town has 24800 people. The population grows by 10% every year. What will the population be after 2 years?
38. 38.A town has 39600 people. The population grows by 25% every year. What will the population be after 2 years?
39. 39.Find the compound interest on ₹28800 at 20% per year for 1 year, compounded every year (in ₹).
40. 40.What is the difference between the compound interest and the simple interest on ₹55000 at 12% per year for 2 years (in ₹)?

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets