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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 3 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹42500 at 4% per year for 2 years (in ₹)?
  2. 2.A town has 47800 people. The population grows by 4% every year. What will the population be after 1 year?
  3. 3.What is the difference between the compound interest and the simple interest on ₹50800 at 25% per year for 2 years (in ₹)?
  4. 4.What amount will ₹60000 grow to in 3 years at 10% per year compound interest (in ₹)?
  5. 5.Find the compound interest on ₹5700 at 10% per year for 1 year, compounded every year (in ₹).
  6. 6.What amount will ₹59100 grow to in 1 year at 20% per year compound interest (in ₹)?
  7. 7.What amount will ₹4200 grow to in 1 year at 15% per year compound interest (in ₹)?
  8. 8.What is the difference between the compound interest and the simple interest on ₹3200 at 5% per year for 2 years (in ₹)?
  9. 9.A scooter is worth ₹16100. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
  10. 10.A town has 28500 people. The population grows by 20% every year. What will the population be after 3 years?
  11. 11.A town has 57400 people. The population grows by 8% every year. What will the population be after 1 year?
  12. 12.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?
  13. 13.A scooter is worth ₹37000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  14. 14.A town has 12900 people. The population grows by 15% every year. What will the population be after 1 year?
  15. 15.Find the compound interest on ₹38400 at 15% per year for 2 years, compounded every year (in ₹).
  16. 16.Find the compound interest on ₹9400 at 10% per year for 1 year, compounded every year (in ₹).
  17. 17.A town has 39500 people. The population grows by 25% every year. What will the population be after 1 year?
  18. 18.Find the compound interest on ₹46000 at 10% per year for 1 year, compounded every year (in ₹).
  19. 19.What is the difference between the compound interest and the simple interest on ₹24000 at 15% per year for 2 years (in ₹)?
  20. 20.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹25000 at 12% per year for 2 years (in ₹)?
  22. 22.What amount will ₹50600 grow to in 1 year at 25% per year compound interest (in ₹)?
  23. 23.A scooter is worth ₹44700. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  24. 24.A scooter is worth ₹17400. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  25. 25.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
  26. 26.A town has 27100 people. The population grows by 25% every year. What will the population be after 1 year?
  27. 27.What amount will ₹25200 grow to in 1 year at 15% per year compound interest (in ₹)?
  28. 28.What amount will ₹57500 grow to in 2 years at 12% per year compound interest (in ₹)?
  29. 29.A scooter is worth ₹35000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  30. 30.A town has 9300 people. The population grows by 10% every year. What will the population be after 1 year?
  31. 31.A scooter is worth ₹57600. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  32. 32.A scooter is worth ₹58600. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  33. 33.What amount will ₹32800 grow to in 2 years at 25% per year compound interest (in ₹)?
  34. 34.What amount will ₹55000 grow to in 3 years at 20% per year compound interest (in ₹)?
  35. 35.Find the compound interest on ₹50000 at 4% per year for 1 year, compounded every year (in ₹).
  36. 36.What amount will ₹13500 grow to in 3 years at 20% per year compound interest (in ₹)?
  37. 37.What amount will ₹25800 grow to in 2 years at 10% per year compound interest (in ₹)?
  38. 38.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
  39. 39.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
  40. 40.What is the difference between the compound interest and the simple interest on ₹22500 at 4% per year for 2 years (in ₹)?

Answer key

  1. 68
  2. 49712
  3. 3175
  4. 79860
  5. 570
  6. 70920
  7. 4830
  8. 8
  9. 14168
  10. 49248
  11. 61992
  12. 12
  13. 26973
  14. 14835
  15. 12384
  16. 940
  17. 49375
  18. 4600
  19. 540
  20. 9261
  21. 360
  22. 63250
  23. 42912
  24. 16008
  25. 64827
  26. 33875
  27. 28980
  28. 72128
  29. 32256
  30. 10230
  31. 24300
  32. 52740
  33. 51250
  34. 95040
  35. 2000
  36. 23328
  37. 31218
  38. 384
  39. 8827
  40. 36

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