Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 300 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹26800 at 15% per year for 2 years (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹25900 at 10% per year for 2 years (in ₹)?
3. 3.A town has 17000 people. The population grows by 10% every year. What will the population be after 3 years?
4. 4.A scooter is worth ₹39600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
6. 6.A scooter is worth ₹25000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
7. 7.Find the compound interest on ₹19800 at 8% per year for 1 year, compounded every year (in ₹).
8. 8.What amount will ₹57000 grow to in 1 year at 5% per year compound interest (in ₹)?
9. 9.What amount will ₹13000 grow to in 2 years at 20% per year compound interest (in ₹)?
10. 10.Find the compound interest on ₹8000 at 5% per year for 2 years, compounded every year (in ₹).
11. 11.A scooter is worth ₹60000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
12. 12.A town has 5200 people. The population grows by 10% every year. What will the population be after 1 year?
13. 13.Find the compound interest on ₹38000 at 10% per year for 1 year, compounded every year (in ₹).
14. 14.Find the compound interest on ₹9200 at 8% per year for 1 year, compounded every year (in ₹).
15. 15.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?
16. 16.Find the compound interest on ₹43700 at 12% per year for 1 year, compounded every year (in ₹).
17. 17.A town has 43000 people. The population grows by 12% every year. What will the population be after 1 year?
18. 18.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
19. 19.A scooter is worth ₹14600. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
20. 20.Find the compound interest on ₹22400 at 15% per year for 1 year, compounded every year (in ₹).
21. 21.Find the compound interest on ₹12600 at 5% per year for 1 year, compounded every year (in ₹).
22. 22.What amount will ₹39200 grow to in 1 year at 20% per year compound interest (in ₹)?
23. 23.What amount will ₹35400 grow to in 1 year at 12% per year compound interest (in ₹)?
24. 24.A scooter is worth ₹22500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹21600 at 10% per year for 2 years (in ₹)?
26. 26.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
27. 27.What is the difference between the compound interest and the simple interest on ₹22400 at 15% per year for 2 years (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹46000 at 5% per year for 2 years (in ₹)?
29. 29.What amount will ₹15600 grow to in 2 years at 15% per year compound interest (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹15300 at 10% per year for 2 years (in ₹)?
31. 31.A town has 57200 people. The population grows by 15% every year. What will the population be after 1 year?
32. 32.A scooter is worth ₹58800. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
33. 33.What amount will ₹28800 grow to in 2 years at 25% per year compound interest (in ₹)?
34. 34.A town has 25900 people. The population grows by 5% every year. What will the population be after 1 year?
35. 35.Find the compound interest on ₹2000 at 20% per year for 2 years, compounded every year (in ₹).
36. 36.What amount will ₹18000 grow to in 3 years at 10% per year compound interest (in ₹)?
37. 37.Find the compound interest on ₹37400 at 10% per year for 1 year, compounded every year (in ₹).
38. 38.Find the compound interest on ₹7500 at 8% per year for 2 years, compounded every year (in ₹).
39. 39.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
40. 40.What is the difference between the compound interest and the simple interest on ₹3000 at 20% per year for 2 years (in ₹)?

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