Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 304 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹24800 at 5% per year for 2 years, compounded every year (in ₹).
2. 2.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
4. 4.A town has 44800 people. The population grows by 25% every year. What will the population be after 3 years?
5. 5.A town has 28700 people. The population grows by 8% every year. What will the population be after 1 year?
6. 6.Find the compound interest on ₹10000 at 4% per year for 2 years, compounded every year (in ₹).
7. 7.A town has 9900 people. The population grows by 5% every year. What will the population be after 1 year?
8. 8.Find the compound interest on ₹16700 at 10% per year for 2 years, compounded every year (in ₹).
9. 9.Find the compound interest on ₹5700 at 4% per year for 1 year, compounded every year (in ₹).
10. 10.A scooter is worth ₹20000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹2900 at 10% per year for 2 years (in ₹)?
12. 12.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
13. 13.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
14. 14.Find the compound interest on ₹4800 at 25% per year for 1 year, compounded every year (in ₹).
15. 15.What amount will ₹27500 grow to in 2 years at 4% per year compound interest (in ₹)?
16. 16.Find the compound interest on ₹59200 at 25% per year for 3 years, compounded every year (in ₹).
17. 17.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹30000 at 12% per year for 2 years (in ₹)?
19. 19.A town has 40900 people. The population grows by 5% every year. What will the population be after 1 year?
20. 20.Find the compound interest on ₹2400 at 15% per year for 2 years, compounded every year (in ₹).
21. 21.What amount will ₹45600 grow to in 1 year at 4% per year compound interest (in ₹)?
22. 22.What amount will ₹42600 grow to in 1 year at 10% per year compound interest (in ₹)?
23. 23.Find the compound interest on ₹54000 at 20% per year for 3 years, compounded every year (in ₹).
24. 24.What is the difference between the compound interest and the simple interest on ₹54800 at 25% per year for 2 years (in ₹)?
25. 25.Find the compound interest on ₹30000 at 12% per year for 2 years, compounded every year (in ₹).
26. 26.Find the compound interest on ₹52800 at 15% per year for 2 years, compounded every year (in ₹).
27. 27.What amount will ₹50700 grow to in 1 year at 5% per year compound interest (in ₹)?
28. 28.What amount will ₹56800 grow to in 1 year at 25% per year compound interest (in ₹)?
29. 29.A scooter is worth ₹9900. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
30. 30.What amount will ₹8000 grow to in 3 years at 25% per year compound interest (in ₹)?
31. 31.Find the compound interest on ₹15800 at 8% per year for 1 year, compounded every year (in ₹).
32. 32.What amount will ₹38900 grow to in 2 years at 20% per year compound interest (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹10500 at 10% per year for 2 years (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹50000 at 8% per year for 2 years (in ₹)?
35. 35.What is the difference between the compound interest and the simple interest on ₹22500 at 8% per year for 2 years (in ₹)?
36. 36.What amount will ₹22600 grow to in 2 years at 10% per year compound interest (in ₹)?
37. 37.Find the compound interest on ₹36100 at 12% per year for 1 year, compounded every year (in ₹).
38. 38.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?
39. 39.A scooter is worth ₹52000. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
40. 40.Find the compound interest on ₹49600 at 25% per year for 3 years, compounded every year (in ₹).

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets