Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 307 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹10900 at 10% per year for 2 years (in ₹)?
2. 2.A town has 55300 people. The population grows by 10% every year. What will the population be after 1 year?
3. 3.Find the compound interest on ₹30400 at 25% per year for 3 years, compounded every year (in ₹).
4. 4.A scooter is worth ₹59600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
5. 5.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
6. 6.A town has 43000 people. The population grows by 20% every year. What will the population be after 3 years?
7. 7.A scooter is worth ₹30400. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
8. 8.Find the compound interest on ₹23100 at 10% per year for 2 years, compounded every year (in ₹).
9. 9.What amount will ₹39400 grow to in 2 years at 20% per year compound interest (in ₹)?
10. 10.Find the compound interest on ₹35000 at 10% per year for 3 years, compounded every year (in ₹).
11. 11.A scooter is worth ₹6000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
12. 12.Find the compound interest on ₹56000 at 25% per year for 2 years, compounded every year (in ₹).
13. 13.What amount will ₹4500 grow to in 3 years at 20% per year compound interest (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹54400 at 25% per year for 2 years (in ₹)?
15. 15.Find the compound interest on ₹49700 at 20% per year for 1 year, compounded every year (in ₹).
16. 16.What amount will ₹33200 grow to in 1 year at 25% per year compound interest (in ₹)?
17. 17.Find the compound interest on ₹30000 at 25% per year for 1 year, compounded every year (in ₹).
18. 18.Find the compound interest on ₹8400 at 25% per year for 1 year, compounded every year (in ₹).
19. 19.A scooter is worth ₹19500. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
20. 20.A town has 15000 people. The population grows by 8% every year. What will the population be after 2 years?
21. 21.What amount will ₹38600 grow to in 2 years at 10% per year compound interest (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹30000 at 4% per year for 2 years (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹19200 at 25% per year for 2 years (in ₹)?
24. 24.What amount will ₹15600 grow to in 2 years at 20% per year compound interest (in ₹)?
25. 25.A scooter is worth ₹39800. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
26. 26.A town has 22000 people. The population grows by 25% every year. What will the population be after 2 years?
27. 27.What amount will ₹5300 grow to in 1 year at 15% per year compound interest (in ₹)?
28. 28.A town has 17000 people. The population grows by 10% every year. What will the population be after 3 years?
29. 29.A scooter is worth ₹16800. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
30. 30.What amount will ₹56000 grow to in 2 years at 25% per year compound interest (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹20000 at 4% per year for 2 years (in ₹)?
32. 32.Find the compound interest on ₹11200 at 10% per year for 2 years, compounded every year (in ₹).
33. 33.A town has 5000 people. The population grows by 8% every year. What will the population be after 2 years?
34. 34.What is the difference between the compound interest and the simple interest on ₹32500 at 4% per year for 2 years (in ₹)?
35. 35.What is the difference between the compound interest and the simple interest on ₹36800 at 15% per year for 2 years (in ₹)?
36. 36.What amount will ₹10000 grow to in 3 years at 10% per year compound interest (in ₹)?
37. 37.What is the difference between the compound interest and the simple interest on ₹32500 at 12% per year for 2 years (in ₹)?
38. 38.Find the compound interest on ₹5300 at 5% per year for 1 year, compounded every year (in ₹).
39. 39.Find the compound interest on ₹19500 at 5% per year for 1 year, compounded every year (in ₹).
40. 40.A scooter is worth ₹39600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?

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