Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹24100 at 8% per year for 1 year, compounded every year (in ₹).
- 2.What amount will ₹49600 grow to in 1 year at 15% per year compound interest (in ₹)?
- 3.Find the compound interest on ₹12500 at 8% per year for 2 years, compounded every year (in ₹).
- 4.A scooter is worth ₹59400. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
- 5.A scooter is worth ₹17800. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 6.What is the difference between the compound interest and the simple interest on ₹2500 at 8% per year for 2 years (in ₹)?
- 7.What is the difference between the compound interest and the simple interest on ₹25200 at 25% per year for 2 years (in ₹)?
- 8.A scooter is worth ₹6800. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 9.What is the difference between the compound interest and the simple interest on ₹55000 at 4% per year for 2 years (in ₹)?
- 10.What amount will ₹56000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 11.A town has 16000 people. The population grows by 5% every year. What will the population be after 1 year?
- 12.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
- 13.What amount will ₹48000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 14.Find the compound interest on ₹25000 at 10% per year for 3 years, compounded every year (in ₹).
- 15.Find the compound interest on ₹27500 at 4% per year for 2 years, compounded every year (in ₹).
- 16.What amount will ₹54400 grow to in 3 years at 25% per year compound interest (in ₹)?
- 17.What is the difference between the compound interest and the simple interest on ₹34800 at 25% per year for 2 years (in ₹)?
- 18.Find the compound interest on ₹57000 at 8% per year for 1 year, compounded every year (in ₹).
- 19.What is the difference between the compound interest and the simple interest on ₹10500 at 20% per year for 2 years (in ₹)?
- 20.What is the difference between the compound interest and the simple interest on ₹19600 at 20% per year for 2 years (in ₹)?
- 21.What amount will ₹52500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 22.Find the compound interest on ₹24800 at 25% per year for 2 years, compounded every year (in ₹).
- 23.Find the compound interest on ₹22400 at 25% per year for 3 years, compounded every year (in ₹).
- 24.Find the compound interest on ₹55900 at 5% per year for 1 year, compounded every year (in ₹).
- 25.What amount will ₹10900 grow to in 1 year at 12% per year compound interest (in ₹)?
- 26.Find the compound interest on ₹29400 at 20% per year for 1 year, compounded every year (in ₹).
- 27.A town has 24000 people. The population grows by 25% every year. What will the population be after 2 years?
- 28.A scooter is worth ₹7700. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 29.What amount will ₹43100 grow to in 1 year at 25% per year compound interest (in ₹)?
- 30.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 31.What amount will ₹52600 grow to in 1 year at 15% per year compound interest (in ₹)?
- 32.What is the difference between the compound interest and the simple interest on ₹36400 at 5% per year for 2 years (in ₹)?
- 33.A town has 39400 people. The population grows by 25% every year. What will the population be after 1 year?
- 34.What amount will ₹59500 grow to in 3 years at 20% per year compound interest (in ₹)?
- 35.What amount will ₹44400 grow to in 2 years at 5% per year compound interest (in ₹)?
- 36.What amount will ₹21500 grow to in 1 year at 10% per year compound interest (in ₹)?
- 37.What amount will ₹42800 grow to in 2 years at 25% per year compound interest (in ₹)?
- 38.What amount will ₹34000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 39.Find the compound interest on ₹6300 at 15% per year for 1 year, compounded every year (in ₹).
- 40.A town has 40400 people. The population grows by 4% every year. What will the population be after 1 year?
Answer key
- 1928
- 57040
- 2080
- 47520
- 14418
- 16
- 1575
- 5508
- 88
- 85169
- 16800
- 8827
- 73002
- 8275
- 2244
- 106250
- 2175
- 4560
- 420
- 784
- 61236
- 13950
- 21350
- 2795
- 12208
- 5880
- 37500
- 6237
- 53875
- 18522
- 60490
- 91
- 49250
- 102816
- 48951
- 23650
- 66875
- 45254
- 945
- 42016
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