Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹6400 at 5% per year for 2 years (in ₹)?
- 2.A scooter is worth ₹24100. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
- 3.Find the compound interest on ₹57900 at 12% per year for 1 year, compounded every year (in ₹).
- 4.Find the compound interest on ₹49900 at 4% per year for 1 year, compounded every year (in ₹).
- 5.A scooter is worth ₹47500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 6.A scooter is worth ₹60000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 7.A town has 16000 people. The population grows by 25% every year. What will the population be after 3 years?
- 8.A town has 3100 people. The population grows by 12% every year. What will the population be after 1 year?
- 9.What is the difference between the compound interest and the simple interest on ₹57000 at 20% per year for 2 years (in ₹)?
- 10.What amount will ₹2500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 11.Find the compound interest on ₹28400 at 5% per year for 2 years, compounded every year (in ₹).
- 12.Find the compound interest on ₹12300 at 25% per year for 1 year, compounded every year (in ₹).
- 13.A town has 22500 people. The population grows by 12% every year. What will the population be after 2 years?
- 14.What amount will ₹56000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 15.A scooter is worth ₹10600. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
- 16.What amount will ₹38000 grow to in 2 years at 15% per year compound interest (in ₹)?
- 17.Find the compound interest on ₹33200 at 10% per year for 1 year, compounded every year (in ₹).
- 18.What amount will ₹34800 grow to in 1 year at 12% per year compound interest (in ₹)?
- 19.What is the difference between the compound interest and the simple interest on ₹33500 at 10% per year for 2 years (in ₹)?
- 20.What is the difference between the compound interest and the simple interest on ₹8700 at 10% per year for 2 years (in ₹)?
- 21.A scooter is worth ₹32000. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 22.Find the compound interest on ₹34500 at 20% per year for 3 years, compounded every year (in ₹).
- 23.A scooter is worth ₹50000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 24.What is the difference between the compound interest and the simple interest on ₹45400 at 20% per year for 2 years (in ₹)?
- 25.Find the compound interest on ₹31200 at 10% per year for 2 years, compounded every year (in ₹).
- 26.What is the difference between the compound interest and the simple interest on ₹26800 at 5% per year for 2 years (in ₹)?
- 27.What amount will ₹25000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 28.What amount will ₹12500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 29.A town has 4800 people. The population grows by 25% every year. What will the population be after 3 years?
- 30.What amount will ₹45000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 31.A town has 41600 people. The population grows by 5% every year. What will the population be after 2 years?
- 32.Find the compound interest on ₹27400 at 10% per year for 2 years, compounded every year (in ₹).
- 33.Find the compound interest on ₹4500 at 10% per year for 2 years, compounded every year (in ₹).
- 34.Find the compound interest on ₹35200 at 4% per year for 1 year, compounded every year (in ₹).
- 35.What is the difference between the compound interest and the simple interest on ₹5600 at 20% per year for 2 years (in ₹)?
- 36.A scooter is worth ₹56000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 37.What amount will ₹35100 grow to in 1 year at 15% per year compound interest (in ₹)?
- 38.Find the compound interest on ₹10800 at 15% per year for 2 years, compounded every year (in ₹).
- 39.A town has 42500 people. The population grows by 12% every year. What will the population be after 2 years?
- 40.Find the compound interest on ₹42900 at 10% per year for 2 years, compounded every year (in ₹).
Answer key
- 16
- 19280
- 6948
- 1996
- 43776
- 55296
- 31250
- 3472
- 2280
- 2704
- 2911
- 3075
- 28224
- 85169
- 7950
- 50255
- 3320
- 38976
- 335
- 87
- 13500
- 25116
- 46080
- 1816
- 6552
- 67
- 29160
- 15680
- 9375
- 48672
- 45864
- 5754
- 945
- 1408
- 224
- 48013
- 40365
- 3483
- 53312
- 9009
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