Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What amount will ₹21700 grow to in 1 year at 8% per year compound interest (in ₹)?
- 2.A town has 57500 people. The population grows by 5% every year. What will the population be after 1 year?
- 3.A scooter is worth ₹47500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 4.What is the difference between the compound interest and the simple interest on ₹17600 at 10% per year for 2 years (in ₹)?
- 5.Find the compound interest on ₹4100 at 20% per year for 1 year, compounded every year (in ₹).
- 6.What is the difference between the compound interest and the simple interest on ₹48800 at 5% per year for 2 years (in ₹)?
- 7.Find the compound interest on ₹15000 at 10% per year for 2 years, compounded every year (in ₹).
- 8.Find the compound interest on ₹31900 at 5% per year for 1 year, compounded every year (in ₹).
- 9.What is the difference between the compound interest and the simple interest on ₹48800 at 15% per year for 2 years (in ₹)?
- 10.A town has 26500 people. The population grows by 5% every year. What will the population be after 1 year?
- 11.What is the difference between the compound interest and the simple interest on ₹43800 at 20% per year for 2 years (in ₹)?
- 12.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
- 13.What is the difference between the compound interest and the simple interest on ₹21600 at 5% per year for 2 years (in ₹)?
- 14.What amount will ₹12600 grow to in 1 year at 5% per year compound interest (in ₹)?
- 15.What is the difference between the compound interest and the simple interest on ₹12200 at 20% per year for 2 years (in ₹)?
- 16.A scooter is worth ₹26800. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 17.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 18.Find the compound interest on ₹27000 at 10% per year for 3 years, compounded every year (in ₹).
- 19.A town has 14800 people. The population grows by 5% every year. What will the population be after 1 year?
- 20.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 21.What amount will ₹58000 grow to in 2 years at 25% per year compound interest (in ₹)?
- 22.A town has 56000 people. The population grows by 15% every year. What will the population be after 3 years?
- 23.Find the compound interest on ₹50000 at 4% per year for 2 years, compounded every year (in ₹).
- 24.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
- 25.What amount will ₹12800 grow to in 2 years at 5% per year compound interest (in ₹)?
- 26.A scooter is worth ₹12500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 27.What amount will ₹31700 grow to in 1 year at 15% per year compound interest (in ₹)?
- 28.What amount will ₹12000 grow to in 1 year at 20% per year compound interest (in ₹)?
- 29.What amount will ₹48000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 30.What is the difference between the compound interest and the simple interest on ₹10000 at 5% per year for 2 years (in ₹)?
- 31.Find the compound interest on ₹14200 at 20% per year for 2 years, compounded every year (in ₹).
- 32.What is the difference between the compound interest and the simple interest on ₹60000 at 5% per year for 2 years (in ₹)?
- 33.Find the compound interest on ₹51400 at 12% per year for 1 year, compounded every year (in ₹).
- 34.Find the compound interest on ₹14400 at 20% per year for 2 years, compounded every year (in ₹).
- 35.What is the difference between the compound interest and the simple interest on ₹22500 at 4% per year for 2 years (in ₹)?
- 36.A scooter is worth ₹56000. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 37.Find the compound interest on ₹31400 at 25% per year for 1 year, compounded every year (in ₹).
- 38.What is the difference between the compound interest and the simple interest on ₹12400 at 5% per year for 2 years (in ₹)?
- 39.Find the compound interest on ₹17000 at 4% per year for 1 year, compounded every year (in ₹).
- 40.What amount will ₹51500 grow to in 3 years at 20% per year compound interest (in ₹)?
Answer key
- 23436
- 60375
- 40204
- 176
- 820
- 122
- 3150
- 1595
- 1098
- 27825
- 1752
- 1261
- 54
- 13230
- 488
- 19363
- 18522
- 8937
- 15540
- 60835
- 90625
- 85169
- 4080
- 32
- 14112
- 9680
- 36455
- 14400
- 73002
- 25
- 6248
- 150
- 6168
- 6336
- 36
- 47600
- 7850
- 31
- 680
- 88992
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