Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 32 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹37600 at 15% per year for 2 years (in ₹)?
2. 2.A town has 43000 people. The population grows by 25% every year. What will the population be after 1 year?
3. 3.Find the compound interest on ₹52400 at 25% per year for 2 years, compounded every year (in ₹).
4. 4.A town has 36800 people. The population grows by 5% every year. What will the population be after 1 year?
5. 5.Find the compound interest on ₹21800 at 5% per year for 1 year, compounded every year (in ₹).
6. 6.Find the compound interest on ₹19100 at 10% per year for 2 years, compounded every year (in ₹).
7. 7.What amount will ₹20500 grow to in 3 years at 20% per year compound interest (in ₹)?
8. 8.What amount will ₹29400 grow to in 1 year at 4% per year compound interest (in ₹)?
9. 9.Find the compound interest on ₹8800 at 12% per year for 1 year, compounded every year (in ₹).
10. 10.What is the difference between the compound interest and the simple interest on ₹36000 at 5% per year for 2 years (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹16200 at 20% per year for 2 years (in ₹)?
12. 12.Find the compound interest on ₹14000 at 20% per year for 3 years, compounded every year (in ₹).
13. 13.A town has 21600 people. The population grows by 4% every year. What will the population be after 1 year?
14. 14.A town has 39200 people. The population grows by 4% every year. What will the population be after 1 year?
15. 15.Find the compound interest on ₹25000 at 20% per year for 3 years, compounded every year (in ₹).
16. 16.Find the compound interest on ₹12100 at 10% per year for 1 year, compounded every year (in ₹).
17. 17.Find the compound interest on ₹28800 at 8% per year for 1 year, compounded every year (in ₹).
18. 18.Find the compound interest on ₹24100 at 12% per year for 1 year, compounded every year (in ₹).
19. 19.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?
20. 20.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
21. 21.Find the compound interest on ₹23000 at 10% per year for 3 years, compounded every year (in ₹).
22. 22.What is the difference between the compound interest and the simple interest on ₹40400 at 5% per year for 2 years (in ₹)?
23. 23.Find the compound interest on ₹23500 at 5% per year for 1 year, compounded every year (in ₹).
24. 24.A town has 22500 people. The population grows by 8% every year. What will the population be after 2 years?
25. 25.What is the difference between the compound interest and the simple interest on ₹48000 at 10% per year for 2 years (in ₹)?
26. 26.Find the compound interest on ₹19200 at 5% per year for 2 years, compounded every year (in ₹).
27. 27.A town has 3800 people. The population grows by 5% every year. What will the population be after 1 year?
28. 28.A town has 34400 people. The population grows by 15% every year. What will the population be after 2 years?
29. 29.A town has 10300 people. The population grows by 10% every year. What will the population be after 2 years?
30. 30.A scooter is worth ₹10000. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
31. 31.A scooter is worth ₹10000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
32. 32.What amount will ₹47500 grow to in 2 years at 12% per year compound interest (in ₹)?
33. 33.What amount will ₹38700 grow to in 1 year at 4% per year compound interest (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹32500 at 8% per year for 2 years (in ₹)?
35. 35.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
36. 36.What amount will ₹44000 grow to in 2 years at 20% per year compound interest (in ₹)?
37. 37.What amount will ₹4300 grow to in 1 year at 20% per year compound interest (in ₹)?
38. 38.Find the compound interest on ₹35000 at 20% per year for 3 years, compounded every year (in ₹).
39. 39.A scooter is worth ₹33000. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
40. 40.What is the difference between the compound interest and the simple interest on ₹34400 at 5% per year for 2 years (in ₹)?

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