← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 321 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹59500 at 20% per year for 2 years (in ₹)?
  2. 2.What amount will ₹45800 grow to in 1 year at 5% per year compound interest (in ₹)?
  3. 3.What is the difference between the compound interest and the simple interest on ₹2800 at 5% per year for 2 years (in ₹)?
  4. 4.A scooter is worth ₹51200. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  5. 5.A scooter is worth ₹1600. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  6. 6.A town has 39400 people. The population grows by 10% every year. What will the population be after 2 years?
  7. 7.Find the compound interest on ₹2500 at 12% per year for 2 years, compounded every year (in ₹).
  8. 8.What is the difference between the compound interest and the simple interest on ₹6400 at 5% per year for 2 years (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹12000 at 15% per year for 2 years (in ₹)?
  10. 10.What amount will ₹40000 grow to in 1 year at 10% per year compound interest (in ₹)?
  11. 11.What amount will ₹12200 grow to in 1 year at 5% per year compound interest (in ₹)?
  12. 12.A scooter is worth ₹56600. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  13. 13.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
  14. 14.What amount will ₹24000 grow to in 3 years at 20% per year compound interest (in ₹)?
  15. 15.What amount will ₹52000 grow to in 3 years at 10% per year compound interest (in ₹)?
  16. 16.A town has 38000 people. The population grows by 20% every year. What will the population be after 3 years?
  17. 17.Find the compound interest on ₹20400 at 5% per year for 2 years, compounded every year (in ₹).
  18. 18.A scooter is worth ₹9100. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  19. 19.Find the compound interest on ₹54300 at 10% per year for 2 years, compounded every year (in ₹).
  20. 20.What amount will ₹9100 grow to in 1 year at 15% per year compound interest (in ₹)?
  21. 21.What amount will ₹56000 grow to in 3 years at 10% per year compound interest (in ₹)?
  22. 22.A scooter is worth ₹2500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  23. 23.Find the compound interest on ₹40000 at 10% per year for 3 years, compounded every year (in ₹).
  24. 24.A scooter is worth ₹46000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
  25. 25.What amount will ₹35600 grow to in 2 years at 25% per year compound interest (in ₹)?
  26. 26.Find the compound interest on ₹23600 at 15% per year for 2 years, compounded every year (in ₹).
  27. 27.What is the difference between the compound interest and the simple interest on ₹4500 at 20% per year for 2 years (in ₹)?
  28. 28.Find the compound interest on ₹38400 at 25% per year for 3 years, compounded every year (in ₹).
  29. 29.Find the compound interest on ₹53600 at 4% per year for 1 year, compounded every year (in ₹).
  30. 30.What is the difference between the compound interest and the simple interest on ₹18000 at 25% per year for 2 years (in ₹)?
  31. 31.What amount will ₹3200 grow to in 2 years at 25% per year compound interest (in ₹)?
  32. 32.What amount will ₹49800 grow to in 2 years at 20% per year compound interest (in ₹)?
  33. 33.What amount will ₹20200 grow to in 2 years at 20% per year compound interest (in ₹)?
  34. 34.A town has 2000 people. The population grows by 10% every year. What will the population be after 3 years?
  35. 35.Find the compound interest on ₹54700 at 25% per year for 1 year, compounded every year (in ₹).
  36. 36.What is the difference between the compound interest and the simple interest on ₹52400 at 20% per year for 2 years (in ₹)?
  37. 37.A scooter is worth ₹15000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  38. 38.What is the difference between the compound interest and the simple interest on ₹57500 at 8% per year for 2 years (in ₹)?
  39. 39.A scooter is worth ₹36500. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  40. 40.What amount will ₹10300 grow to in 1 year at 15% per year compound interest (in ₹)?

Answer key

  1. 2380
  2. 48090
  3. 7
  4. 21600
  5. 675
  6. 47674
  7. 636
  8. 16
  9. 270
  10. 44000
  11. 12810
  12. 42450
  13. 2522
  14. 41472
  15. 69212
  16. 65664
  17. 2091
  18. 6825
  19. 11403
  20. 10465
  21. 74536
  22. 2304
  23. 13240
  24. 23552
  25. 55625
  26. 7611
  27. 180
  28. 36600
  29. 2144
  30. 1125
  31. 5000
  32. 71712
  33. 29088
  34. 2662
  35. 13675
  36. 2096
  37. 10935
  38. 368
  39. 33580
  40. 11845

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets