Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 323 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹22500 at 4% per year for 2 years (in ₹)?
2. 2.Find the compound interest on ₹35200 at 25% per year for 1 year, compounded every year (in ₹).
3. 3.A town has 49200 people. The population grows by 5% every year. What will the population be after 2 years?
4. 4.What is the difference between the compound interest and the simple interest on ₹50000 at 8% per year for 2 years (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹53200 at 5% per year for 2 years (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹9200 at 15% per year for 2 years (in ₹)?
7. 7.Find the compound interest on ₹3500 at 4% per year for 1 year, compounded every year (in ₹).
8. 8.A scooter is worth ₹26700. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
9. 9.What amount will ₹28800 grow to in 3 years at 25% per year compound interest (in ₹)?
10. 10.A scooter is worth ₹50000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
11. 11.A town has 34000 people. The population grows by 25% every year. What will the population be after 1 year?
12. 12.What is the difference between the compound interest and the simple interest on ₹12500 at 10% per year for 2 years (in ₹)?
13. 13.Find the compound interest on ₹41600 at 25% per year for 3 years, compounded every year (in ₹).
14. 14.What is the difference between the compound interest and the simple interest on ₹53600 at 15% per year for 2 years (in ₹)?
15. 15.A scooter is worth ₹25000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹18400 at 15% per year for 2 years (in ₹)?
17. 17.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹48400 at 25% per year for 2 years (in ₹)?
19. 19.What amount will ₹56000 grow to in 1 year at 20% per year compound interest (in ₹)?
20. 20.A town has 5400 people. The population grows by 20% every year. What will the population be after 2 years?
21. 21.A town has 27600 people. The population grows by 8% every year. What will the population be after 1 year?
22. 22.What amount will ₹24000 grow to in 3 years at 15% per year compound interest (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹21600 at 25% per year for 2 years (in ₹)?
24. 24.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
25. 25.What is the difference between the compound interest and the simple interest on ₹49200 at 15% per year for 2 years (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹5000 at 4% per year for 2 years (in ₹)?
27. 27.Find the compound interest on ₹12000 at 20% per year for 1 year, compounded every year (in ₹).
28. 28.A town has 57900 people. The population grows by 20% every year. What will the population be after 1 year?
29. 29.What is the difference between the compound interest and the simple interest on ₹38200 at 10% per year for 2 years (in ₹)?
30. 30.Find the compound interest on ₹13900 at 20% per year for 1 year, compounded every year (in ₹).
31. 31.What amount will ₹7400 grow to in 2 years at 20% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹23300 at 20% per year for 1 year, compounded every year (in ₹).
33. 33.A scooter is worth ₹14000. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹13200 at 20% per year for 2 years (in ₹)?
35. 35.Find the compound interest on ₹9600 at 25% per year for 3 years, compounded every year (in ₹).
36. 36.What amount will ₹22000 grow to in 2 years at 25% per year compound interest (in ₹)?
37. 37.A town has 39800 people. The population grows by 25% every year. What will the population be after 1 year?
38. 38.A town has 35000 people. The population grows by 8% every year. What will the population be after 2 years?
39. 39.Find the compound interest on ₹41500 at 20% per year for 2 years, compounded every year (in ₹).
40. 40.Find the compound interest on ₹2900 at 20% per year for 1 year, compounded every year (in ₹).

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets