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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 328 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹57500 at 8% per year for 2 years, compounded every year (in ₹).
  2. 2.What is the difference between the compound interest and the simple interest on ₹45000 at 4% per year for 2 years (in ₹)?
  3. 3.What is the difference between the compound interest and the simple interest on ₹55300 at 20% per year for 2 years (in ₹)?
  4. 4.Find the compound interest on ₹35000 at 8% per year for 2 years, compounded every year (in ₹).
  5. 5.What amount will ₹7200 grow to in 2 years at 15% per year compound interest (in ₹)?
  6. 6.A scooter is worth ₹39400. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
  7. 7.Find the compound interest on ₹50400 at 25% per year for 2 years, compounded every year (in ₹).
  8. 8.What is the difference between the compound interest and the simple interest on ₹52500 at 4% per year for 2 years (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹24800 at 10% per year for 2 years (in ₹)?
  10. 10.What is the difference between the compound interest and the simple interest on ₹55400 at 20% per year for 2 years (in ₹)?
  11. 11.A town has 37300 people. The population grows by 5% every year. What will the population be after 1 year?
  12. 12.A town has 24000 people. The population grows by 20% every year. What will the population be after 3 years?
  13. 13.What amount will ₹54000 grow to in 2 years at 25% per year compound interest (in ₹)?
  14. 14.Find the compound interest on ₹16500 at 15% per year for 1 year, compounded every year (in ₹).
  15. 15.Find the compound interest on ₹30000 at 20% per year for 3 years, compounded every year (in ₹).
  16. 16.What amount will ₹20000 grow to in 3 years at 10% per year compound interest (in ₹)?
  17. 17.What amount will ₹25000 grow to in 1 year at 10% per year compound interest (in ₹)?
  18. 18.A town has 16100 people. The population grows by 5% every year. What will the population be after 1 year?
  19. 19.What is the difference between the compound interest and the simple interest on ₹38900 at 20% per year for 2 years (in ₹)?
  20. 20.What is the difference between the compound interest and the simple interest on ₹26400 at 15% per year for 2 years (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹42000 at 25% per year for 2 years (in ₹)?
  22. 22.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
  23. 23.A scooter is worth ₹19200. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  24. 24.A town has 56000 people. The population grows by 15% every year. What will the population be after 3 years?
  25. 25.Find the compound interest on ₹13000 at 10% per year for 1 year, compounded every year (in ₹).
  26. 26.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
  27. 27.What is the difference between the compound interest and the simple interest on ₹24800 at 15% per year for 2 years (in ₹)?
  28. 28.What amount will ₹17700 grow to in 1 year at 15% per year compound interest (in ₹)?
  29. 29.Find the compound interest on ₹35400 at 10% per year for 2 years, compounded every year (in ₹).
  30. 30.What is the difference between the compound interest and the simple interest on ₹35000 at 8% per year for 2 years (in ₹)?
  31. 31.Find the compound interest on ₹23500 at 5% per year for 1 year, compounded every year (in ₹).
  32. 32.What is the difference between the compound interest and the simple interest on ₹48000 at 5% per year for 2 years (in ₹)?
  33. 33.A scooter is worth ₹51200. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
  34. 34.Find the compound interest on ₹6300 at 10% per year for 2 years, compounded every year (in ₹).
  35. 35.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
  36. 36.What is the difference between the compound interest and the simple interest on ₹12800 at 15% per year for 2 years (in ₹)?
  37. 37.What is the difference between the compound interest and the simple interest on ₹50000 at 8% per year for 2 years (in ₹)?
  38. 38.Find the compound interest on ₹35200 at 5% per year for 2 years, compounded every year (in ₹).
  39. 39.Find the compound interest on ₹38000 at 5% per year for 2 years, compounded every year (in ₹).
  40. 40.What is the difference between the compound interest and the simple interest on ₹44800 at 10% per year for 2 years (in ₹)?

Answer key

  1. 9568
  2. 72
  3. 2212
  4. 5824
  5. 9522
  6. 25216
  7. 28350
  8. 84
  9. 248
  10. 2216
  11. 39165
  12. 41472
  13. 84375
  14. 2475
  15. 21840
  16. 26620
  17. 27500
  18. 16905
  19. 1556
  20. 594
  21. 2625
  22. 180
  23. 8100
  24. 85169
  25. 1300
  26. 1261
  27. 558
  28. 20355
  29. 7434
  30. 224
  31. 1175
  32. 120
  33. 43520
  34. 1323
  35. 25002
  36. 288
  37. 320
  38. 3608
  39. 3895
  40. 448

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