Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 331 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹17300 grow to in 1 year at 5% per year compound interest (in ₹)?
2. 2.Find the compound interest on ₹6000 at 10% per year for 3 years, compounded every year (in ₹).
3. 3.What is the difference between the compound interest and the simple interest on ₹21200 at 15% per year for 2 years (in ₹)?
4. 4.A town has 11600 people. The population grows by 5% every year. What will the population be after 2 years?
5. 5.Find the compound interest on ₹7900 at 10% per year for 1 year, compounded every year (in ₹).
6. 6.A scooter is worth ₹16000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹35000 at 20% per year for 2 years (in ₹)?
8. 8.A scooter is worth ₹27900. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
9. 9.Find the compound interest on ₹47800 at 12% per year for 1 year, compounded every year (in ₹).
10. 10.Find the compound interest on ₹49800 at 10% per year for 1 year, compounded every year (in ₹).
11. 11.Find the compound interest on ₹39200 at 5% per year for 2 years, compounded every year (in ₹).
12. 12.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
14. 14.What amount will ₹17600 grow to in 1 year at 20% per year compound interest (in ₹)?
15. 15.A scooter is worth ₹17500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹50000 at 25% per year for 2 years (in ₹)?
17. 17.What amount will ₹55200 grow to in 2 years at 25% per year compound interest (in ₹)?
18. 18.What amount will ₹11000 grow to in 3 years at 10% per year compound interest (in ₹)?
19. 19.A scooter is worth ₹6400. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
20. 20.What amount will ₹25600 grow to in 3 years at 25% per year compound interest (in ₹)?
21. 21.What amount will ₹48200 grow to in 1 year at 5% per year compound interest (in ₹)?
22. 22.What amount will ₹31500 grow to in 1 year at 8% per year compound interest (in ₹)?
23. 23.A scooter is worth ₹48400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
24. 24.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
25. 25.Find the compound interest on ₹18600 at 15% per year for 1 year, compounded every year (in ₹).
26. 26.What is the difference between the compound interest and the simple interest on ₹41800 at 10% per year for 2 years (in ₹)?
27. 27.What amount will ₹55800 grow to in 1 year at 12% per year compound interest (in ₹)?
28. 28.Find the compound interest on ₹41300 at 10% per year for 1 year, compounded every year (in ₹).
29. 29.What is the difference between the compound interest and the simple interest on ₹37200 at 5% per year for 2 years (in ₹)?
30. 30.Find the compound interest on ₹30400 at 10% per year for 2 years, compounded every year (in ₹).
31. 31.What amount will ₹10000 grow to in 2 years at 12% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹46800 at 5% per year for 1 year, compounded every year (in ₹).
33. 33.What is the difference between the compound interest and the simple interest on ₹45600 at 5% per year for 2 years (in ₹)?
34. 34.Find the compound interest on ₹40000 at 25% per year for 1 year, compounded every year (in ₹).
35. 35.What is the difference between the compound interest and the simple interest on ₹46800 at 20% per year for 2 years (in ₹)?
36. 36.A town has 13000 people. The population grows by 10% every year. What will the population be after 3 years?
37. 37.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
38. 38.A town has 17600 people. The population grows by 5% every year. What will the population be after 2 years?
39. 39.What amount will ₹10000 grow to in 2 years at 4% per year compound interest (in ₹)?
40. 40.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?

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