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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 334 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What amount will ₹51400 grow to in 2 years at 20% per year compound interest (in ₹)?
  2. 2.What amount will ₹6200 grow to in 2 years at 10% per year compound interest (in ₹)?
  3. 3.A town has 55500 people. The population grows by 20% every year. What will the population be after 3 years?
  4. 4.Find the compound interest on ₹19800 at 20% per year for 1 year, compounded every year (in ₹).
  5. 5.What amount will ₹3600 grow to in 2 years at 15% per year compound interest (in ₹)?
  6. 6.What amount will ₹32500 grow to in 2 years at 4% per year compound interest (in ₹)?
  7. 7.Find the compound interest on ₹2000 at 15% per year for 2 years, compounded every year (in ₹).
  8. 8.Find the compound interest on ₹3200 at 15% per year for 2 years, compounded every year (in ₹).
  9. 9.Find the compound interest on ₹31400 at 4% per year for 1 year, compounded every year (in ₹).
  10. 10.What amount will ₹20000 grow to in 2 years at 4% per year compound interest (in ₹)?
  11. 11.A scooter is worth ₹28600. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  12. 12.A town has 4300 people. The population grows by 15% every year. What will the population be after 1 year?
  13. 13.What is the difference between the compound interest and the simple interest on ₹28800 at 5% per year for 2 years (in ₹)?
  14. 14.What amount will ₹14400 grow to in 2 years at 20% per year compound interest (in ₹)?
  15. 15.A town has 32000 people. The population grows by 15% every year. What will the population be after 3 years?
  16. 16.Find the compound interest on ₹11200 at 20% per year for 1 year, compounded every year (in ₹).
  17. 17.Find the compound interest on ₹15000 at 12% per year for 2 years, compounded every year (in ₹).
  18. 18.What amount will ₹30000 grow to in 3 years at 10% per year compound interest (in ₹)?
  19. 19.Find the compound interest on ₹2500 at 12% per year for 1 year, compounded every year (in ₹).
  20. 20.What amount will ₹9000 grow to in 1 year at 10% per year compound interest (in ₹)?
  21. 21.A scooter is worth ₹30200. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  22. 22.What is the difference between the compound interest and the simple interest on ₹25200 at 25% per year for 2 years (in ₹)?
  23. 23.A scooter is worth ₹56000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  24. 24.Find the compound interest on ₹58400 at 5% per year for 1 year, compounded every year (in ₹).
  25. 25.What is the difference between the compound interest and the simple interest on ₹18800 at 10% per year for 2 years (in ₹)?
  26. 26.A scooter is worth ₹56300. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
  27. 27.A town has 44700 people. The population grows by 12% every year. What will the population be after 1 year?
  28. 28.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
  29. 29.Find the compound interest on ₹23300 at 20% per year for 2 years, compounded every year (in ₹).
  30. 30.Find the compound interest on ₹7500 at 4% per year for 2 years, compounded every year (in ₹).
  31. 31.Find the compound interest on ₹10300 at 10% per year for 1 year, compounded every year (in ₹).
  32. 32.What amount will ₹8200 grow to in 1 year at 8% per year compound interest (in ₹)?
  33. 33.A scooter is worth ₹57500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  34. 34.Find the compound interest on ₹46400 at 25% per year for 3 years, compounded every year (in ₹).
  35. 35.Find the compound interest on ₹16300 at 20% per year for 2 years, compounded every year (in ₹).
  36. 36.A scooter is worth ₹44400. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  37. 37.What is the difference between the compound interest and the simple interest on ₹34000 at 10% per year for 2 years (in ₹)?
  38. 38.What is the difference between the compound interest and the simple interest on ₹35500 at 20% per year for 2 years (in ₹)?
  39. 39.Find the compound interest on ₹55000 at 8% per year for 2 years, compounded every year (in ₹).
  40. 40.Find the compound interest on ₹17100 at 5% per year for 1 year, compounded every year (in ₹).

Answer key

  1. 74016
  2. 7502
  3. 95904
  4. 3960
  5. 4761
  6. 35152
  7. 645
  8. 1032
  9. 1256
  10. 21632
  11. 21450
  12. 4945
  13. 72
  14. 20736
  15. 48668
  16. 2240
  17. 3816
  18. 39930
  19. 300
  20. 9900
  21. 24160
  22. 1575
  23. 40824
  24. 2920
  25. 188
  26. 47855
  27. 50064
  28. 72
  29. 10252
  30. 612
  31. 1030
  32. 8856
  33. 44528
  34. 44225
  35. 7172
  36. 42180
  37. 340
  38. 1420
  39. 9152
  40. 855

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