Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What amount will ₹6200 grow to in 2 years at 10% per year compound interest (in ₹)?
- 2.A scooter is worth ₹50100. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 3.What is the difference between the compound interest and the simple interest on ₹40000 at 4% per year for 2 years (in ₹)?
- 4.What amount will ₹59000 grow to in 1 year at 5% per year compound interest (in ₹)?
- 5.What amount will ₹6400 grow to in 2 years at 25% per year compound interest (in ₹)?
- 6.Find the compound interest on ₹6100 at 8% per year for 1 year, compounded every year (in ₹).
- 7.What amount will ₹59200 grow to in 1 year at 5% per year compound interest (in ₹)?
- 8.What is the difference between the compound interest and the simple interest on ₹37500 at 8% per year for 2 years (in ₹)?
- 9.Find the compound interest on ₹41400 at 4% per year for 1 year, compounded every year (in ₹).
- 10.Find the compound interest on ₹44000 at 5% per year for 2 years, compounded every year (in ₹).
- 11.Find the compound interest on ₹58500 at 4% per year for 1 year, compounded every year (in ₹).
- 12.Find the compound interest on ₹16200 at 10% per year for 1 year, compounded every year (in ₹).
- 13.A town has 56800 people. The population grows by 5% every year. What will the population be after 2 years?
- 14.Find the compound interest on ₹17500 at 12% per year for 2 years, compounded every year (in ₹).
- 15.What amount will ₹50000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 16.A town has 30000 people. The population grows by 8% every year. What will the population be after 2 years?
- 17.What amount will ₹7800 grow to in 1 year at 5% per year compound interest (in ₹)?
- 18.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
- 19.A scooter is worth ₹48200. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 20.A town has 32800 people. The population grows by 5% every year. What will the population be after 1 year?
- 21.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
- 22.Find the compound interest on ₹32200 at 10% per year for 2 years, compounded every year (in ₹).
- 23.A scooter is worth ₹11800. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
- 24.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
- 25.A town has 50600 people. The population grows by 10% every year. What will the population be after 2 years?
- 26.What is the difference between the compound interest and the simple interest on ₹22800 at 5% per year for 2 years (in ₹)?
- 27.What is the difference between the compound interest and the simple interest on ₹35000 at 8% per year for 2 years (in ₹)?
- 28.Find the compound interest on ₹42000 at 5% per year for 2 years, compounded every year (in ₹).
- 29.A scooter is worth ₹45600. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 30.A scooter is worth ₹6700. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 31.Find the compound interest on ₹17700 at 12% per year for 1 year, compounded every year (in ₹).
- 32.What amount will ₹56000 grow to in 3 years at 25% per year compound interest (in ₹)?
- 33.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
- 34.A town has 27200 people. The population grows by 10% every year. What will the population be after 1 year?
- 35.Find the compound interest on ₹52800 at 15% per year for 2 years, compounded every year (in ₹).
- 36.Find the compound interest on ₹33300 at 5% per year for 1 year, compounded every year (in ₹).
- 37.A scooter is worth ₹48100. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 38.What is the difference between the compound interest and the simple interest on ₹2500 at 8% per year for 2 years (in ₹)?
- 39.What amount will ₹31500 grow to in 3 years at 20% per year compound interest (in ₹)?
- 40.Find the compound interest on ₹2200 at 5% per year for 1 year, compounded every year (in ₹).
Answer key
- 7502
- 42585
- 64
- 61950
- 10000
- 488
- 62160
- 240
- 1656
- 4510
- 2340
- 1620
- 62622
- 4452
- 58320
- 34992
- 8190
- 3783
- 40970
- 34440
- 12501
- 6762
- 9440
- 5044
- 61226
- 57
- 224
- 4305
- 32946
- 6365
- 2124
- 109375
- 6305
- 29920
- 17028
- 1665
- 46176
- 16
- 54432
- 110
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