Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 344 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹47800 at 10% per year for 2 years, compounded every year (in ₹).
2. 2.What is the difference between the compound interest and the simple interest on ₹32500 at 4% per year for 2 years (in ₹)?
3. 3.Find the compound interest on ₹2000 at 10% per year for 3 years, compounded every year (in ₹).
4. 4.What is the difference between the compound interest and the simple interest on ₹57500 at 12% per year for 2 years (in ₹)?
5. 5.What amount will ₹28400 grow to in 2 years at 5% per year compound interest (in ₹)?
6. 6.Find the compound interest on ₹59600 at 5% per year for 2 years, compounded every year (in ₹).
7. 7.What amount will ₹56000 grow to in 3 years at 25% per year compound interest (in ₹)?
8. 8.Find the compound interest on ₹2100 at 20% per year for 2 years, compounded every year (in ₹).
9. 9.What is the difference between the compound interest and the simple interest on ₹41600 at 5% per year for 2 years (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹44800 at 20% per year for 2 years (in ₹)?
11. 11.A scooter is worth ₹43200. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
12. 12.Find the compound interest on ₹14600 at 8% per year for 1 year, compounded every year (in ₹).
13. 13.A scooter is worth ₹9100. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
14. 14.A town has 35000 people. The population grows by 20% every year. What will the population be after 1 year?
15. 15.A town has 49000 people. The population grows by 25% every year. What will the population be after 1 year?
16. 16.What amount will ₹42000 grow to in 2 years at 25% per year compound interest (in ₹)?
17. 17.A scooter is worth ₹31300. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹3200 at 5% per year for 2 years (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹16400 at 20% per year for 2 years (in ₹)?
20. 20.What amount will ₹24000 grow to in 3 years at 15% per year compound interest (in ₹)?
21. 21.What amount will ₹20000 grow to in 2 years at 8% per year compound interest (in ₹)?
22. 22.What amount will ₹58400 grow to in 1 year at 12% per year compound interest (in ₹)?
23. 23.Find the compound interest on ₹47600 at 5% per year for 2 years, compounded every year (in ₹).
24. 24.Find the compound interest on ₹50200 at 8% per year for 1 year, compounded every year (in ₹).
25. 25.What is the difference between the compound interest and the simple interest on ₹20000 at 12% per year for 2 years (in ₹)?
26. 26.Find the compound interest on ₹39000 at 20% per year for 2 years, compounded every year (in ₹).
27. 27.What amount will ₹8100 grow to in 1 year at 5% per year compound interest (in ₹)?
28. 28.A town has 39800 people. The population grows by 10% every year. What will the population be after 1 year?
29. 29.A scooter is worth ₹9300. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
30. 30.A scooter is worth ₹53100. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
31. 31.A scooter is worth ₹20400. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
32. 32.What amount will ₹4600 grow to in 1 year at 8% per year compound interest (in ₹)?
33. 33.What amount will ₹20000 grow to in 3 years at 10% per year compound interest (in ₹)?
34. 34.Find the compound interest on ₹37700 at 25% per year for 1 year, compounded every year (in ₹).
35. 35.Find the compound interest on ₹45000 at 12% per year for 2 years, compounded every year (in ₹).
36. 36.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
37. 37.A town has 9900 people. The population grows by 8% every year. What will the population be after 1 year?
38. 38.Find the compound interest on ₹9000 at 15% per year for 1 year, compounded every year (in ₹).
39. 39.What is the difference between the compound interest and the simple interest on ₹41200 at 25% per year for 2 years (in ₹)?
40. 40.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?

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