Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 349 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹55000 at 8% per year for 2 years (in ₹)?
2. 2.What amount will ₹35000 grow to in 2 years at 4% per year compound interest (in ₹)?
3. 3.Find the compound interest on ₹48000 at 8% per year for 1 year, compounded every year (in ₹).
4. 4.Find the compound interest on ₹34500 at 20% per year for 2 years, compounded every year (in ₹).
5. 5.A town has 49200 people. The population grows by 15% every year. What will the population be after 2 years?
6. 6.A town has 18500 people. The population grows by 4% every year. What will the population be after 1 year?
7. 7.A town has 55000 people. The population grows by 20% every year. What will the population be after 2 years?
8. 8.What amount will ₹27500 grow to in 2 years at 8% per year compound interest (in ₹)?
9. 9.A scooter is worth ₹34800. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
10. 10.What amount will ₹57900 grow to in 1 year at 20% per year compound interest (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹18700 at 20% per year for 2 years (in ₹)?
12. 12.A town has 33000 people. The population grows by 10% every year. What will the population be after 3 years?
13. 13.Find the compound interest on ₹32000 at 20% per year for 3 years, compounded every year (in ₹).
14. 14.A town has 35500 people. The population grows by 5% every year. What will the population be after 1 year?
15. 15.Find the compound interest on ₹48000 at 5% per year for 2 years, compounded every year (in ₹).
16. 16.What amount will ₹16400 grow to in 1 year at 12% per year compound interest (in ₹)?
17. 17.What amount will ₹14500 grow to in 1 year at 4% per year compound interest (in ₹)?
18. 18.What amount will ₹7700 grow to in 2 years at 20% per year compound interest (in ₹)?
19. 19.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
20. 20.What amount will ₹1600 grow to in 3 years at 25% per year compound interest (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹27600 at 5% per year for 2 years (in ₹)?
22. 22.A scooter is worth ₹40000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
24. 24.A town has 43200 people. The population grows by 15% every year. What will the population be after 2 years?
25. 25.Find the compound interest on ₹18600 at 4% per year for 1 year, compounded every year (in ₹).
26. 26.Find the compound interest on ₹30200 at 25% per year for 1 year, compounded every year (in ₹).
27. 27.A town has 5000 people. The population grows by 8% every year. What will the population be after 2 years?
28. 28.A town has 31100 people. The population grows by 10% every year. What will the population be after 1 year?
29. 29.A town has 36000 people. The population grows by 15% every year. What will the population be after 2 years?
30. 30.What amount will ₹29200 grow to in 2 years at 15% per year compound interest (in ₹)?
31. 31.What amount will ₹46800 grow to in 1 year at 4% per year compound interest (in ₹)?
32. 32.A scooter is worth ₹15000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
33. 33.Find the compound interest on ₹45100 at 20% per year for 2 years, compounded every year (in ₹).
34. 34.What amount will ₹6200 grow to in 1 year at 12% per year compound interest (in ₹)?
35. 35.What is the difference between the compound interest and the simple interest on ₹17500 at 12% per year for 2 years (in ₹)?
36. 36.Find the compound interest on ₹14300 at 25% per year for 1 year, compounded every year (in ₹).
37. 37.What is the difference between the compound interest and the simple interest on ₹43900 at 10% per year for 2 years (in ₹)?
38. 38.A town has 35000 people. The population grows by 4% every year. What will the population be after 2 years?
39. 39.Find the compound interest on ₹23800 at 4% per year for 1 year, compounded every year (in ₹).
40. 40.A scooter is worth ₹44700. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets