Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 353 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹42900 at 10% per year for 2 years (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹46900 at 20% per year for 2 years (in ₹)?
3. 3.A town has 34900 people. The population grows by 4% every year. What will the population be after 1 year?
4. 4.What is the difference between the compound interest and the simple interest on ₹32500 at 4% per year for 2 years (in ₹)?
5. 5.A town has 18800 people. The population grows by 10% every year. What will the population be after 2 years?
6. 6.What is the difference between the compound interest and the simple interest on ₹27500 at 12% per year for 2 years (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹22000 at 25% per year for 2 years (in ₹)?
8. 8.Find the compound interest on ₹43200 at 5% per year for 2 years, compounded every year (in ₹).
9. 9.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
10. 10.Find the compound interest on ₹39300 at 10% per year for 2 years, compounded every year (in ₹).
11. 11.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹45200 at 25% per year for 2 years (in ₹)?
13. 13.Find the compound interest on ₹58000 at 10% per year for 3 years, compounded every year (in ₹).
14. 14.What is the difference between the compound interest and the simple interest on ₹23800 at 10% per year for 2 years (in ₹)?
15. 15.Find the compound interest on ₹16700 at 20% per year for 1 year, compounded every year (in ₹).
16. 16.Find the compound interest on ₹49200 at 5% per year for 2 years, compounded every year (in ₹).
17. 17.A scooter is worth ₹9400. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
18. 18.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
19. 19.A town has 8000 people. The population grows by 10% every year. What will the population be after 2 years?
20. 20.What is the difference between the compound interest and the simple interest on ₹2900 at 20% per year for 2 years (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹34400 at 15% per year for 2 years (in ₹)?
22. 22.Find the compound interest on ₹14000 at 8% per year for 1 year, compounded every year (in ₹).
23. 23.Find the compound interest on ₹43100 at 5% per year for 1 year, compounded every year (in ₹).
24. 24.What amount will ₹54000 grow to in 1 year at 10% per year compound interest (in ₹)?
25. 25.A scooter is worth ₹20100. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹4800 at 10% per year for 2 years (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹6300 at 10% per year for 2 years (in ₹)?
28. 28.What amount will ₹31000 grow to in 1 year at 25% per year compound interest (in ₹)?
29. 29.A town has 47600 people. The population grows by 25% every year. What will the population be after 2 years?
30. 30.A town has 47500 people. The population grows by 10% every year. What will the population be after 2 years?
31. 31.What amount will ₹33200 grow to in 2 years at 5% per year compound interest (in ₹)?
32. 32.What amount will ₹33700 grow to in 1 year at 10% per year compound interest (in ₹)?
33. 33.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
34. 34.A scooter is worth ₹31600. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
35. 35.Find the compound interest on ₹20000 at 4% per year for 1 year, compounded every year (in ₹).
36. 36.What amount will ₹27500 grow to in 2 years at 4% per year compound interest (in ₹)?
37. 37.What amount will ₹34400 grow to in 2 years at 15% per year compound interest (in ₹)?
38. 38.A scooter is worth ₹43900. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹37800 at 10% per year for 2 years (in ₹)?
40. 40.What is the difference between the compound interest and the simple interest on ₹50000 at 8% per year for 2 years (in ₹)?

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