Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
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- 1.A town has 2000 people. The population grows by 5% every year. What will the population be after 2 years?
- 2.Find the compound interest on ₹3000 at 10% per year for 3 years, compounded every year (in ₹).
- 3.A scooter is worth ₹48000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 4.What amount will ₹3000 grow to in 1 year at 5% per year compound interest (in ₹)?
- 5.What amount will ₹48800 grow to in 2 years at 15% per year compound interest (in ₹)?
- 6.What amount will ₹11900 grow to in 1 year at 15% per year compound interest (in ₹)?
- 7.Find the compound interest on ₹3200 at 10% per year for 1 year, compounded every year (in ₹).
- 8.What is the difference between the compound interest and the simple interest on ₹18000 at 5% per year for 2 years (in ₹)?
- 9.A scooter is worth ₹11400. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 10.Find the compound interest on ₹19600 at 5% per year for 2 years, compounded every year (in ₹).
- 11.What is the difference between the compound interest and the simple interest on ₹58800 at 25% per year for 2 years (in ₹)?
- 12.Find the compound interest on ₹32800 at 25% per year for 2 years, compounded every year (in ₹).
- 13.What is the difference between the compound interest and the simple interest on ₹32300 at 20% per year for 2 years (in ₹)?
- 14.A scooter is worth ₹7200. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 15.A town has 47200 people. The population grows by 15% every year. What will the population be after 2 years?
- 16.What is the difference between the compound interest and the simple interest on ₹21200 at 25% per year for 2 years (in ₹)?
- 17.What is the difference between the compound interest and the simple interest on ₹26800 at 25% per year for 2 years (in ₹)?
- 18.Find the compound interest on ₹51300 at 20% per year for 2 years, compounded every year (in ₹).
- 19.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 20.What amount will ₹57500 grow to in 1 year at 20% per year compound interest (in ₹)?
- 21.What amount will ₹27900 grow to in 1 year at 20% per year compound interest (in ₹)?
- 22.A scooter is worth ₹41100. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 23.What is the difference between the compound interest and the simple interest on ₹8400 at 15% per year for 2 years (in ₹)?
- 24.Find the compound interest on ₹25800 at 8% per year for 1 year, compounded every year (in ₹).
- 25.What amount will ₹38300 grow to in 1 year at 25% per year compound interest (in ₹)?
- 26.What is the difference between the compound interest and the simple interest on ₹39300 at 10% per year for 2 years (in ₹)?
- 27.What is the difference between the compound interest and the simple interest on ₹22500 at 12% per year for 2 years (in ₹)?
- 28.Find the compound interest on ₹32000 at 20% per year for 3 years, compounded every year (in ₹).
- 29.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
- 30.Find the compound interest on ₹3700 at 15% per year for 1 year, compounded every year (in ₹).
- 31.What is the difference between the compound interest and the simple interest on ₹39700 at 10% per year for 2 years (in ₹)?
- 32.What is the difference between the compound interest and the simple interest on ₹14800 at 25% per year for 2 years (in ₹)?
- 33.Find the compound interest on ₹31200 at 4% per year for 1 year, compounded every year (in ₹).
- 34.What is the difference between the compound interest and the simple interest on ₹38100 at 20% per year for 2 years (in ₹)?
- 35.What amount will ₹2000 grow to in 1 year at 8% per year compound interest (in ₹)?
- 36.A scooter is worth ₹29800. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 37.A town has 15000 people. The population grows by 8% every year. What will the population be after 2 years?
- 38.What amount will ₹23000 grow to in 2 years at 20% per year compound interest (in ₹)?
- 39.Find the compound interest on ₹31000 at 12% per year for 1 year, compounded every year (in ₹).
- 40.Find the compound interest on ₹34400 at 15% per year for 2 years, compounded every year (in ₹).
Answer key
- 2205
- 993
- 34992
- 3150
- 64538
- 13685
- 320
- 45
- 9690
- 2009
- 3675
- 18450
- 1292
- 5202
- 62422
- 1325
- 1675
- 22572
- 48668
- 69000
- 33480
- 37812
- 189
- 2064
- 47875
- 393
- 324
- 23296
- 576
- 555
- 397
- 925
- 1248
- 1524
- 2160
- 24138
- 17496
- 33120
- 3720
- 11094
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