Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹3800 at 10% per year for 1 year, compounded every year (in ₹).
- 2.What is the difference between the compound interest and the simple interest on ₹24800 at 5% per year for 2 years (in ₹)?
- 3.Find the compound interest on ₹24400 at 5% per year for 2 years, compounded every year (in ₹).
- 4.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
- 5.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
- 6.Find the compound interest on ₹58200 at 12% per year for 1 year, compounded every year (in ₹).
- 7.What amount will ₹14000 grow to in 2 years at 15% per year compound interest (in ₹)?
- 8.Find the compound interest on ₹30000 at 20% per year for 3 years, compounded every year (in ₹).
- 9.Find the compound interest on ₹16200 at 5% per year for 1 year, compounded every year (in ₹).
- 10.Find the compound interest on ₹51600 at 10% per year for 1 year, compounded every year (in ₹).
- 11.Find the compound interest on ₹14400 at 25% per year for 3 years, compounded every year (in ₹).
- 12.A town has 34000 people. The population grows by 10% every year. What will the population be after 1 year?
- 13.Find the compound interest on ₹11700 at 10% per year for 1 year, compounded every year (in ₹).
- 14.A scooter is worth ₹25200. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 15.Find the compound interest on ₹52800 at 25% per year for 3 years, compounded every year (in ₹).
- 16.What is the difference between the compound interest and the simple interest on ₹50400 at 5% per year for 2 years (in ₹)?
- 17.Find the compound interest on ₹40400 at 20% per year for 2 years, compounded every year (in ₹).
- 18.What amount will ₹18800 grow to in 2 years at 20% per year compound interest (in ₹)?
- 19.What amount will ₹53000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 20.A scooter is worth ₹4800. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 21.A town has 40000 people. The population grows by 25% every year. What will the population be after 3 years?
- 22.What amount will ₹7500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 23.What amount will ₹20800 grow to in 3 years at 25% per year compound interest (in ₹)?
- 24.What amount will ₹40000 grow to in 1 year at 15% per year compound interest (in ₹)?
- 25.What is the difference between the compound interest and the simple interest on ₹51000 at 20% per year for 2 years (in ₹)?
- 26.Find the compound interest on ₹35000 at 8% per year for 2 years, compounded every year (in ₹).
- 27.Find the compound interest on ₹32000 at 10% per year for 3 years, compounded every year (in ₹).
- 28.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
- 29.Find the compound interest on ₹19000 at 10% per year for 3 years, compounded every year (in ₹).
- 30.A scooter is worth ₹12300. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 31.What amount will ₹29300 grow to in 1 year at 8% per year compound interest (in ₹)?
- 32.What is the difference between the compound interest and the simple interest on ₹32500 at 4% per year for 2 years (in ₹)?
- 33.Find the compound interest on ₹8400 at 5% per year for 1 year, compounded every year (in ₹).
- 34.Find the compound interest on ₹36500 at 10% per year for 2 years, compounded every year (in ₹).
- 35.What is the difference between the compound interest and the simple interest on ₹18800 at 5% per year for 2 years (in ₹)?
- 36.What is the difference between the compound interest and the simple interest on ₹56000 at 20% per year for 2 years (in ₹)?
- 37.A town has 42000 people. The population grows by 10% every year. What will the population be after 3 years?
- 38.What is the difference between the compound interest and the simple interest on ₹31100 at 20% per year for 2 years (in ₹)?
- 39.What is the difference between the compound interest and the simple interest on ₹14300 at 10% per year for 2 years (in ₹)?
- 40.Find the compound interest on ₹41400 at 10% per year for 1 year, compounded every year (in ₹).
Answer key
- 380
- 62
- 2501
- 6305
- 16
- 6984
- 18515
- 21840
- 810
- 5160
- 13725
- 37400
- 1170
- 21420
- 50325
- 126
- 17776
- 27072
- 70543
- 4332
- 78125
- 9408
- 40625
- 46000
- 2040
- 5824
- 10592
- 55566
- 6289
- 11685
- 31644
- 52
- 420
- 7665
- 47
- 2240
- 55902
- 1244
- 143
- 4140
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