Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 36 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹14700 grow to in 1 year at 20% per year compound interest (in ₹)?
2. 2.What amount will ₹2500 grow to in 2 years at 8% per year compound interest (in ₹)?
3. 3.Find the compound interest on ₹44000 at 25% per year for 2 years, compounded every year (in ₹).
4. 4.Find the compound interest on ₹8000 at 25% per year for 3 years, compounded every year (in ₹).
5. 5.Find the compound interest on ₹7500 at 20% per year for 1 year, compounded every year (in ₹).
6. 6.What is the difference between the compound interest and the simple interest on ₹11600 at 5% per year for 2 years (in ₹)?
7. 7.A town has 7400 people. The population grows by 4% every year. What will the population be after 1 year?
8. 8.What is the difference between the compound interest and the simple interest on ₹14900 at 20% per year for 2 years (in ₹)?
9. 9.A scooter is worth ₹56000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
10. 10.What amount will ₹20900 grow to in 1 year at 15% per year compound interest (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹32500 at 12% per year for 2 years (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹54800 at 5% per year for 2 years (in ₹)?
13. 13.A town has 6100 people. The population grows by 15% every year. What will the population be after 1 year?
14. 14.A scooter is worth ₹55600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
15. 15.Find the compound interest on ₹39200 at 5% per year for 2 years, compounded every year (in ₹).
16. 16.What is the difference between the compound interest and the simple interest on ₹25200 at 5% per year for 2 years (in ₹)?
17. 17.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
18. 18.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹37500 at 12% per year for 2 years (in ₹)?
20. 20.Find the compound interest on ₹27500 at 12% per year for 2 years, compounded every year (in ₹).
21. 21.A scooter is worth ₹44600. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
22. 22.What amount will ₹14400 grow to in 2 years at 15% per year compound interest (in ₹)?
23. 23.Find the compound interest on ₹33500 at 20% per year for 3 years, compounded every year (in ₹).
24. 24.A scooter is worth ₹52200. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
25. 25.What amount will ₹36800 grow to in 3 years at 25% per year compound interest (in ₹)?
26. 26.Find the compound interest on ₹43000 at 15% per year for 1 year, compounded every year (in ₹).
27. 27.What amount will ₹39400 grow to in 2 years at 10% per year compound interest (in ₹)?
28. 28.Find the compound interest on ₹24000 at 10% per year for 2 years, compounded every year (in ₹).
29. 29.A town has 4800 people. The population grows by 25% every year. What will the population be after 3 years?
30. 30.Find the compound interest on ₹47900 at 15% per year for 1 year, compounded every year (in ₹).
31. 31.A scooter is worth ₹3600. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹45000 at 8% per year for 2 years (in ₹)?
33. 33.What amount will ₹34800 grow to in 1 year at 10% per year compound interest (in ₹)?
34. 34.A town has 13100 people. The population grows by 4% every year. What will the population be after 1 year?
35. 35.What is the difference between the compound interest and the simple interest on ₹42000 at 15% per year for 2 years (in ₹)?
36. 36.A town has 32000 people. The population grows by 15% every year. What will the population be after 3 years?
37. 37.What amount will ₹49000 grow to in 3 years at 10% per year compound interest (in ₹)?
38. 38.Find the compound interest on ₹37600 at 25% per year for 2 years, compounded every year (in ₹).
39. 39.A scooter is worth ₹13600. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
40. 40.A town has 5200 people. The population grows by 10% every year. What will the population be after 1 year?

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