Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 362 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 45000 people. The population grows by 4% every year. What will the population be after 2 years?
2. 2.Find the compound interest on ₹10800 at 15% per year for 1 year, compounded every year (in ₹).
3. 3.What is the difference between the compound interest and the simple interest on ₹6800 at 20% per year for 2 years (in ₹)?
4. 4.Find the compound interest on ₹24500 at 20% per year for 3 years, compounded every year (in ₹).
5. 5.Find the compound interest on ₹16000 at 25% per year for 3 years, compounded every year (in ₹).
6. 6.Find the compound interest on ₹30200 at 10% per year for 2 years, compounded every year (in ₹).
7. 7.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
8. 8.A scooter is worth ₹30000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
9. 9.What amount will ₹35000 grow to in 2 years at 4% per year compound interest (in ₹)?
10. 10.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹49200 at 20% per year for 2 years (in ₹)?
12. 12.A scooter is worth ₹14000. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
13. 13.Find the compound interest on ₹42900 at 12% per year for 1 year, compounded every year (in ₹).
14. 14.What amount will ₹27000 grow to in 3 years at 10% per year compound interest (in ₹)?
15. 15.Find the compound interest on ₹42000 at 10% per year for 3 years, compounded every year (in ₹).
16. 16.A town has 8800 people. The population grows by 5% every year. What will the population be after 1 year?
17. 17.What amount will ₹5900 grow to in 1 year at 10% per year compound interest (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹57200 at 5% per year for 2 years (in ₹)?
19. 19.Find the compound interest on ₹33500 at 15% per year for 1 year, compounded every year (in ₹).
20. 20.Find the compound interest on ₹25200 at 25% per year for 1 year, compounded every year (in ₹).
21. 21.What is the difference between the compound interest and the simple interest on ₹20000 at 4% per year for 2 years (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹25000 at 12% per year for 2 years (in ₹)?
23. 23.What amount will ₹38000 grow to in 2 years at 5% per year compound interest (in ₹)?
24. 24.What amount will ₹12800 grow to in 3 years at 25% per year compound interest (in ₹)?
25. 25.Find the compound interest on ₹6800 at 20% per year for 2 years, compounded every year (in ₹).
26. 26.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
27. 27.Find the compound interest on ₹43200 at 25% per year for 3 years, compounded every year (in ₹).
28. 28.What is the difference between the compound interest and the simple interest on ₹40000 at 5% per year for 2 years (in ₹)?
29. 29.A town has 50200 people. The population grows by 15% every year. What will the population be after 1 year?
30. 30.What amount will ₹30000 grow to in 2 years at 12% per year compound interest (in ₹)?
31. 31.What amount will ₹6400 grow to in 3 years at 25% per year compound interest (in ₹)?
32. 32.What amount will ₹12000 grow to in 2 years at 25% per year compound interest (in ₹)?
33. 33.A scooter is worth ₹51600. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹38800 at 5% per year for 2 years (in ₹)?
35. 35.A scooter is worth ₹23600. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
36. 36.Find the compound interest on ₹45000 at 8% per year for 1 year, compounded every year (in ₹).
37. 37.Find the compound interest on ₹54800 at 5% per year for 1 year, compounded every year (in ₹).
38. 38.A town has 22100 people. The population grows by 25% every year. What will the population be after 1 year?
39. 39.What is the difference between the compound interest and the simple interest on ₹56200 at 20% per year for 2 years (in ₹)?
40. 40.Find the compound interest on ₹40700 at 12% per year for 1 year, compounded every year (in ₹).

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets