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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 370 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹9200 at 25% per year for 2 years (in ₹)?
  2. 2.Find the compound interest on ₹45400 at 10% per year for 2 years, compounded every year (in ₹).
  3. 3.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
  4. 4.Find the compound interest on ₹8900 at 10% per year for 1 year, compounded every year (in ₹).
  5. 5.Find the compound interest on ₹52900 at 20% per year for 2 years, compounded every year (in ₹).
  6. 6.What amount will ₹15600 grow to in 2 years at 15% per year compound interest (in ₹)?
  7. 7.A town has 35500 people. The population grows by 20% every year. What will the population be after 3 years?
  8. 8.Find the compound interest on ₹41500 at 20% per year for 3 years, compounded every year (in ₹).
  9. 9.Find the compound interest on ₹43200 at 25% per year for 2 years, compounded every year (in ₹).
  10. 10.What is the difference between the compound interest and the simple interest on ₹18400 at 5% per year for 2 years (in ₹)?
  11. 11.What is the difference between the compound interest and the simple interest on ₹60000 at 25% per year for 2 years (in ₹)?
  12. 12.What amount will ₹3100 grow to in 1 year at 4% per year compound interest (in ₹)?
  13. 13.Find the compound interest on ₹36500 at 10% per year for 1 year, compounded every year (in ₹).
  14. 14.What amount will ₹47500 grow to in 2 years at 4% per year compound interest (in ₹)?
  15. 15.A town has 19200 people. The population grows by 10% every year. What will the population be after 2 years?
  16. 16.What is the difference between the compound interest and the simple interest on ₹28500 at 20% per year for 2 years (in ₹)?
  17. 17.A town has 34600 people. The population grows by 25% every year. What will the population be after 1 year?
  18. 18.What is the difference between the compound interest and the simple interest on ₹22500 at 8% per year for 2 years (in ₹)?
  19. 19.Find the compound interest on ₹50700 at 25% per year for 1 year, compounded every year (in ₹).
  20. 20.Find the compound interest on ₹12800 at 25% per year for 3 years, compounded every year (in ₹).
  21. 21.What is the difference between the compound interest and the simple interest on ₹34000 at 5% per year for 2 years (in ₹)?
  22. 22.What is the difference between the compound interest and the simple interest on ₹20000 at 8% per year for 2 years (in ₹)?
  23. 23.A scooter is worth ₹12700. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
  24. 24.A town has 57700 people. The population grows by 5% every year. What will the population be after 1 year?
  25. 25.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?
  26. 26.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
  27. 27.What amount will ₹40500 grow to in 1 year at 8% per year compound interest (in ₹)?
  28. 28.What is the difference between the compound interest and the simple interest on ₹4800 at 10% per year for 2 years (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
  30. 30.What amount will ₹49100 grow to in 1 year at 8% per year compound interest (in ₹)?
  31. 31.What is the difference between the compound interest and the simple interest on ₹15000 at 12% per year for 2 years (in ₹)?
  32. 32.Find the compound interest on ₹58400 at 15% per year for 2 years, compounded every year (in ₹).
  33. 33.What is the difference between the compound interest and the simple interest on ₹5200 at 5% per year for 2 years (in ₹)?
  34. 34.A town has 13600 people. The population grows by 20% every year. What will the population be after 1 year?
  35. 35.Find the compound interest on ₹55000 at 8% per year for 2 years, compounded every year (in ₹).
  36. 36.What amount will ₹21000 grow to in 3 years at 20% per year compound interest (in ₹)?
  37. 37.Find the compound interest on ₹21700 at 10% per year for 2 years, compounded every year (in ₹).
  38. 38.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
  39. 39.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
  40. 40.A town has 48000 people. The population grows by 15% every year. What will the population be after 3 years?

Answer key

  1. 575
  2. 9534
  3. 48668
  4. 890
  5. 23276
  6. 20631
  7. 61344
  8. 30212
  9. 24300
  10. 46
  11. 3750
  12. 3224
  13. 3650
  14. 51376
  15. 23232
  16. 1140
  17. 43250
  18. 144
  19. 12675
  20. 12200
  21. 85
  22. 128
  23. 10795
  24. 60585
  25. 336
  26. 1261
  27. 43740
  28. 48
  29. 180
  30. 53028
  31. 216
  32. 18834
  33. 13
  34. 16320
  35. 9152
  36. 36288
  37. 4557
  38. 9261
  39. 25002
  40. 73002

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