Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 372 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹44000 at 25% per year for 2 years (in ₹)?
2. 2.A scooter is worth ₹28500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
3. 3.A scooter is worth ₹17500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
4. 4.Find the compound interest on ₹32700 at 8% per year for 1 year, compounded every year (in ₹).
5. 5.Find the compound interest on ₹33100 at 4% per year for 1 year, compounded every year (in ₹).
6. 6.What amount will ₹16600 grow to in 2 years at 10% per year compound interest (in ₹)?
7. 7.Find the compound interest on ₹4000 at 20% per year for 3 years, compounded every year (in ₹).
8. 8.What amount will ₹43100 grow to in 1 year at 25% per year compound interest (in ₹)?
9. 9.Find the compound interest on ₹20000 at 8% per year for 2 years, compounded every year (in ₹).
10. 10.A scooter is worth ₹51200. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹54000 at 15% per year for 2 years (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹23500 at 20% per year for 2 years (in ₹)?
13. 13.A town has 52000 people. The population grows by 10% every year. What will the population be after 1 year?
14. 14.A town has 8700 people. The population grows by 12% every year. What will the population be after 1 year?
15. 15.What is the difference between the compound interest and the simple interest on ₹36000 at 10% per year for 2 years (in ₹)?
16. 16.Find the compound interest on ₹37900 at 20% per year for 2 years, compounded every year (in ₹).
17. 17.Find the compound interest on ₹27200 at 5% per year for 2 years, compounded every year (in ₹).
18. 18.A scooter is worth ₹56000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
19. 19.A town has 40000 people. The population grows by 4% every year. What will the population be after 2 years?
20. 20.A scooter is worth ₹8300. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
21. 21.What amount will ₹38000 grow to in 1 year at 12% per year compound interest (in ₹)?
22. 22.A scooter is worth ₹44800. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
23. 23.Find the compound interest on ₹26000 at 10% per year for 2 years, compounded every year (in ₹).
24. 24.What amount will ₹4000 grow to in 2 years at 5% per year compound interest (in ₹)?
25. 25.What amount will ₹13500 grow to in 1 year at 8% per year compound interest (in ₹)?
26. 26.A scooter is worth ₹43500. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
27. 27.A scooter is worth ₹34800. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹53000 at 10% per year for 2 years (in ₹)?
29. 29.Find the compound interest on ₹42400 at 25% per year for 1 year, compounded every year (in ₹).
30. 30.What amount will ₹12300 grow to in 1 year at 12% per year compound interest (in ₹)?
31. 31.A scooter is worth ₹48300. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
32. 32.A scooter is worth ₹49900. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
33. 33.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
34. 34.A scooter is worth ₹36400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
35. 35.A town has 57400 people. The population grows by 10% every year. What will the population be after 2 years?
36. 36.Find the compound interest on ₹48700 at 12% per year for 1 year, compounded every year (in ₹).
37. 37.Find the compound interest on ₹45000 at 12% per year for 2 years, compounded every year (in ₹).
38. 38.A town has 30400 people. The population grows by 15% every year. What will the population be after 2 years?
39. 39.Find the compound interest on ₹37200 at 5% per year for 2 years, compounded every year (in ₹).
40. 40.What amount will ₹17600 grow to in 1 year at 25% per year compound interest (in ₹)?

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