Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 374 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
2. 2.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
3. 3.What amount will ₹30700 grow to in 1 year at 10% per year compound interest (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹4400 at 25% per year for 2 years (in ₹)?
5. 5.A scooter is worth ₹42500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹15000 at 4% per year for 2 years (in ₹)?
7. 7.What amount will ₹25600 grow to in 2 years at 20% per year compound interest (in ₹)?
8. 8.A town has 3600 people. The population grows by 20% every year. What will the population be after 2 years?
9. 9.Find the compound interest on ₹35600 at 25% per year for 2 years, compounded every year (in ₹).
10. 10.Find the compound interest on ₹25000 at 8% per year for 2 years, compounded every year (in ₹).
11. 11.Find the compound interest on ₹45000 at 12% per year for 2 years, compounded every year (in ₹).
12. 12.What amount will ₹40600 grow to in 2 years at 10% per year compound interest (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹29900 at 20% per year for 2 years (in ₹)?
14. 14.A scooter is worth ₹3100. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
15. 15.A town has 37000 people. The population grows by 20% every year. What will the population be after 3 years?
16. 16.What is the difference between the compound interest and the simple interest on ₹30000 at 5% per year for 2 years (in ₹)?
17. 17.Find the compound interest on ₹52800 at 12% per year for 1 year, compounded every year (in ₹).
18. 18.What is the difference between the compound interest and the simple interest on ₹55200 at 25% per year for 2 years (in ₹)?
19. 19.Find the compound interest on ₹51700 at 20% per year for 2 years, compounded every year (in ₹).
20. 20.A town has 52800 people. The population grows by 25% every year. What will the population be after 3 years?
21. 21.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
22. 22.A town has 45400 people. The population grows by 5% every year. What will the population be after 1 year?
23. 23.A town has 55000 people. The population grows by 4% every year. What will the population be after 2 years?
24. 24.Find the compound interest on ₹36000 at 5% per year for 1 year, compounded every year (in ₹).
25. 25.Find the compound interest on ₹15400 at 8% per year for 1 year, compounded every year (in ₹).
26. 26.What is the difference between the compound interest and the simple interest on ₹54100 at 20% per year for 2 years (in ₹)?
27. 27.Find the compound interest on ₹23400 at 8% per year for 1 year, compounded every year (in ₹).
28. 28.A scooter is worth ₹18100. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹28800 at 10% per year for 2 years (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹37800 at 10% per year for 2 years (in ₹)?
31. 31.What amount will ₹11500 grow to in 2 years at 10% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹53900 at 10% per year for 2 years, compounded every year (in ₹).
33. 33.A town has 42500 people. The population grows by 8% every year. What will the population be after 2 years?
34. 34.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
35. 35.A scooter is worth ₹17000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
36. 36.What is the difference between the compound interest and the simple interest on ₹25000 at 12% per year for 2 years (in ₹)?
37. 37.A town has 41200 people. The population grows by 25% every year. What will the population be after 1 year?
38. 38.A town has 60000 people. The population grows by 4% every year. What will the population be after 2 years?
39. 39.What is the difference between the compound interest and the simple interest on ₹50000 at 4% per year for 2 years (in ₹)?
40. 40.Find the compound interest on ₹16600 at 12% per year for 1 year, compounded every year (in ₹).

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