Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 379 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹48400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹3200 at 15% per year for 2 years (in ₹)?
3. 3.Find the compound interest on ₹24500 at 20% per year for 3 years, compounded every year (in ₹).
4. 4.A town has 9300 people. The population grows by 10% every year. What will the population be after 2 years?
5. 5.What is the difference between the compound interest and the simple interest on ₹7600 at 25% per year for 2 years (in ₹)?
6. 6.Find the compound interest on ₹35600 at 8% per year for 1 year, compounded every year (in ₹).
7. 7.A scooter is worth ₹24000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
8. 8.Find the compound interest on ₹46000 at 25% per year for 2 years, compounded every year (in ₹).
9. 9.What is the difference between the compound interest and the simple interest on ₹20700 at 20% per year for 2 years (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹35200 at 5% per year for 2 years (in ₹)?
11. 11.What amount will ₹50000 grow to in 2 years at 5% per year compound interest (in ₹)?
12. 12.What amount will ₹22800 grow to in 2 years at 25% per year compound interest (in ₹)?
13. 13.Find the compound interest on ₹48600 at 12% per year for 1 year, compounded every year (in ₹).
14. 14.What is the difference between the compound interest and the simple interest on ₹21200 at 10% per year for 2 years (in ₹)?
15. 15.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
16. 16.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
17. 17.A scooter is worth ₹9200. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
18. 18.What amount will ₹7300 grow to in 1 year at 15% per year compound interest (in ₹)?
19. 19.Find the compound interest on ₹27200 at 25% per year for 3 years, compounded every year (in ₹).
20. 20.A town has 35000 people. The population grows by 8% every year. What will the population be after 2 years?
21. 21.What is the difference between the compound interest and the simple interest on ₹30000 at 12% per year for 2 years (in ₹)?
22. 22.A town has 22500 people. The population grows by 12% every year. What will the population be after 2 years?
23. 23.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?
24. 24.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
25. 25.Find the compound interest on ₹36200 at 20% per year for 2 years, compounded every year (in ₹).
26. 26.A town has 39900 people. The population grows by 5% every year. What will the population be after 1 year?
27. 27.A scooter is worth ₹56500. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
28. 28.A town has 7500 people. The population grows by 12% every year. What will the population be after 2 years?
29. 29.What amount will ₹21500 grow to in 3 years at 20% per year compound interest (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹8000 at 5% per year for 2 years (in ₹)?
31. 31.A scooter is worth ₹20000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
32. 32.What amount will ₹5000 grow to in 2 years at 4% per year compound interest (in ₹)?
33. 33.Find the compound interest on ₹24500 at 5% per year for 1 year, compounded every year (in ₹).
34. 34.What amount will ₹50000 grow to in 2 years at 12% per year compound interest (in ₹)?
35. 35.A scooter is worth ₹27200. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
36. 36.A town has 52000 people. The population grows by 20% every year. What will the population be after 1 year?
37. 37.A town has 4100 people. The population grows by 8% every year. What will the population be after 1 year?
38. 38.What is the difference between the compound interest and the simple interest on ₹14800 at 25% per year for 2 years (in ₹)?
39. 39.Find the compound interest on ₹7400 at 20% per year for 1 year, compounded every year (in ₹).
40. 40.What is the difference between the compound interest and the simple interest on ₹6000 at 5% per year for 2 years (in ₹)?

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