Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹46200 at 4% per year for 1 year, compounded every year (in ₹).
- 2.A town has 15300 people. The population grows by 15% every year. What will the population be after 1 year?
- 3.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
- 4.What is the difference between the compound interest and the simple interest on ₹32500 at 12% per year for 2 years (in ₹)?
- 5.Find the compound interest on ₹45000 at 12% per year for 2 years, compounded every year (in ₹).
- 6.A town has 8400 people. The population grows by 5% every year. What will the population be after 2 years?
- 7.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
- 8.What is the difference between the compound interest and the simple interest on ₹40800 at 15% per year for 2 years (in ₹)?
- 9.Find the compound interest on ₹22200 at 10% per year for 2 years, compounded every year (in ₹).
- 10.A scooter is worth ₹42400. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 11.Find the compound interest on ₹22000 at 10% per year for 3 years, compounded every year (in ₹).
- 12.What is the difference between the compound interest and the simple interest on ₹32000 at 10% per year for 2 years (in ₹)?
- 13.A town has 38000 people. The population grows by 10% every year. What will the population be after 2 years?
- 14.What is the difference between the compound interest and the simple interest on ₹25000 at 4% per year for 2 years (in ₹)?
- 15.A scooter is worth ₹46800. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
- 16.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 17.What is the difference between the compound interest and the simple interest on ₹2800 at 5% per year for 2 years (in ₹)?
- 18.A scooter is worth ₹39100. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 19.What is the difference between the compound interest and the simple interest on ₹53200 at 5% per year for 2 years (in ₹)?
- 20.Find the compound interest on ₹10600 at 10% per year for 1 year, compounded every year (in ₹).
- 21.Find the compound interest on ₹12500 at 12% per year for 2 years, compounded every year (in ₹).
- 22.What is the difference between the compound interest and the simple interest on ₹56800 at 15% per year for 2 years (in ₹)?
- 23.Find the compound interest on ₹35000 at 12% per year for 2 years, compounded every year (in ₹).
- 24.What is the difference between the compound interest and the simple interest on ₹13100 at 20% per year for 2 years (in ₹)?
- 25.What amount will ₹16800 grow to in 2 years at 15% per year compound interest (in ₹)?
- 26.What is the difference between the compound interest and the simple interest on ₹24400 at 15% per year for 2 years (in ₹)?
- 27.What amount will ₹9500 grow to in 1 year at 12% per year compound interest (in ₹)?
- 28.What is the difference between the compound interest and the simple interest on ₹34000 at 5% per year for 2 years (in ₹)?
- 29.A town has 55000 people. The population grows by 12% every year. What will the population be after 2 years?
- 30.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 31.What is the difference between the compound interest and the simple interest on ₹43600 at 15% per year for 2 years (in ₹)?
- 32.What is the difference between the compound interest and the simple interest on ₹57200 at 5% per year for 2 years (in ₹)?
- 33.What amount will ₹22200 grow to in 2 years at 10% per year compound interest (in ₹)?
- 34.What amount will ₹57500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 35.What amount will ₹38400 grow to in 2 years at 25% per year compound interest (in ₹)?
- 36.What is the difference between the compound interest and the simple interest on ₹54800 at 5% per year for 2 years (in ₹)?
- 37.A town has 38400 people. The population grows by 15% every year. What will the population be after 2 years?
- 38.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
- 39.Find the compound interest on ₹59000 at 10% per year for 3 years, compounded every year (in ₹).
- 40.What amount will ₹51300 grow to in 1 year at 15% per year compound interest (in ₹)?
Answer key
- 1848
- 17595
- 576
- 468
- 11448
- 9261
- 7566
- 918
- 4662
- 40280
- 7282
- 320
- 45980
- 40
- 37440
- 24334
- 7
- 33235
- 133
- 1060
- 3180
- 1278
- 8904
- 524
- 22218
- 549
- 10640
- 85
- 68992
- 64827
- 981
- 143
- 26862
- 62192
- 60000
- 137
- 50784
- 32
- 19529
- 58995
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