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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 381 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹46200 at 4% per year for 1 year, compounded every year (in ₹).
  2. 2.A town has 15300 people. The population grows by 15% every year. What will the population be after 1 year?
  3. 3.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹32500 at 12% per year for 2 years (in ₹)?
  5. 5.Find the compound interest on ₹45000 at 12% per year for 2 years, compounded every year (in ₹).
  6. 6.A town has 8400 people. The population grows by 5% every year. What will the population be after 2 years?
  7. 7.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
  8. 8.What is the difference between the compound interest and the simple interest on ₹40800 at 15% per year for 2 years (in ₹)?
  9. 9.Find the compound interest on ₹22200 at 10% per year for 2 years, compounded every year (in ₹).
  10. 10.A scooter is worth ₹42400. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  11. 11.Find the compound interest on ₹22000 at 10% per year for 3 years, compounded every year (in ₹).
  12. 12.What is the difference between the compound interest and the simple interest on ₹32000 at 10% per year for 2 years (in ₹)?
  13. 13.A town has 38000 people. The population grows by 10% every year. What will the population be after 2 years?
  14. 14.What is the difference between the compound interest and the simple interest on ₹25000 at 4% per year for 2 years (in ₹)?
  15. 15.A scooter is worth ₹46800. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  16. 16.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
  17. 17.What is the difference between the compound interest and the simple interest on ₹2800 at 5% per year for 2 years (in ₹)?
  18. 18.A scooter is worth ₹39100. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
  19. 19.What is the difference between the compound interest and the simple interest on ₹53200 at 5% per year for 2 years (in ₹)?
  20. 20.Find the compound interest on ₹10600 at 10% per year for 1 year, compounded every year (in ₹).
  21. 21.Find the compound interest on ₹12500 at 12% per year for 2 years, compounded every year (in ₹).
  22. 22.What is the difference between the compound interest and the simple interest on ₹56800 at 15% per year for 2 years (in ₹)?
  23. 23.Find the compound interest on ₹35000 at 12% per year for 2 years, compounded every year (in ₹).
  24. 24.What is the difference between the compound interest and the simple interest on ₹13100 at 20% per year for 2 years (in ₹)?
  25. 25.What amount will ₹16800 grow to in 2 years at 15% per year compound interest (in ₹)?
  26. 26.What is the difference between the compound interest and the simple interest on ₹24400 at 15% per year for 2 years (in ₹)?
  27. 27.What amount will ₹9500 grow to in 1 year at 12% per year compound interest (in ₹)?
  28. 28.What is the difference between the compound interest and the simple interest on ₹34000 at 5% per year for 2 years (in ₹)?
  29. 29.A town has 55000 people. The population grows by 12% every year. What will the population be after 2 years?
  30. 30.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
  31. 31.What is the difference between the compound interest and the simple interest on ₹43600 at 15% per year for 2 years (in ₹)?
  32. 32.What is the difference between the compound interest and the simple interest on ₹57200 at 5% per year for 2 years (in ₹)?
  33. 33.What amount will ₹22200 grow to in 2 years at 10% per year compound interest (in ₹)?
  34. 34.What amount will ₹57500 grow to in 2 years at 4% per year compound interest (in ₹)?
  35. 35.What amount will ₹38400 grow to in 2 years at 25% per year compound interest (in ₹)?
  36. 36.What is the difference between the compound interest and the simple interest on ₹54800 at 5% per year for 2 years (in ₹)?
  37. 37.A town has 38400 people. The population grows by 15% every year. What will the population be after 2 years?
  38. 38.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
  39. 39.Find the compound interest on ₹59000 at 10% per year for 3 years, compounded every year (in ₹).
  40. 40.What amount will ₹51300 grow to in 1 year at 15% per year compound interest (in ₹)?

Answer key

  1. 1848
  2. 17595
  3. 576
  4. 468
  5. 11448
  6. 9261
  7. 7566
  8. 918
  9. 4662
  10. 40280
  11. 7282
  12. 320
  13. 45980
  14. 40
  15. 37440
  16. 24334
  17. 7
  18. 33235
  19. 133
  20. 1060
  21. 3180
  22. 1278
  23. 8904
  24. 524
  25. 22218
  26. 549
  27. 10640
  28. 85
  29. 68992
  30. 64827
  31. 981
  32. 143
  33. 26862
  34. 62192
  35. 60000
  36. 137
  37. 50784
  38. 32
  39. 19529
  40. 58995

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