Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 384 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹47300 grow to in 1 year at 5% per year compound interest (in ₹)?
2. 2.A town has 16400 people. The population grows by 15% every year. What will the population be after 2 years?
3. 3.What amount will ₹25700 grow to in 2 years at 20% per year compound interest (in ₹)?
4. 4.What amount will ₹14100 grow to in 2 years at 20% per year compound interest (in ₹)?
5. 5.Find the compound interest on ₹12800 at 25% per year for 3 years, compounded every year (in ₹).
6. 6.Find the compound interest on ₹5000 at 4% per year for 2 years, compounded every year (in ₹).
7. 7.A town has 12000 people. The population grows by 5% every year. What will the population be after 2 years?
8. 8.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
9. 9.Find the compound interest on ₹10000 at 12% per year for 2 years, compounded every year (in ₹).
10. 10.Find the compound interest on ₹7400 at 10% per year for 1 year, compounded every year (in ₹).
11. 11.What is the difference between the compound interest and the simple interest on ₹6000 at 20% per year for 2 years (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
13. 13.A scooter is worth ₹24000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
14. 14.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
15. 15.What amount will ₹59200 grow to in 2 years at 25% per year compound interest (in ₹)?
16. 16.Find the compound interest on ₹30000 at 8% per year for 2 years, compounded every year (in ₹).
17. 17.A town has 50000 people. The population grows by 8% every year. What will the population be after 2 years?
18. 18.A town has 28800 people. The population grows by 25% every year. What will the population be after 3 years?
19. 19.Find the compound interest on ₹17700 at 10% per year for 1 year, compounded every year (in ₹).
20. 20.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
21. 21.What amount will ₹11200 grow to in 3 years at 25% per year compound interest (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹50400 at 15% per year for 2 years (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹35200 at 25% per year for 2 years (in ₹)?
24. 24.Find the compound interest on ₹48000 at 10% per year for 2 years, compounded every year (in ₹).
25. 25.Find the compound interest on ₹50000 at 4% per year for 2 years, compounded every year (in ₹).
26. 26.Find the compound interest on ₹2000 at 25% per year for 2 years, compounded every year (in ₹).
27. 27.What is the difference between the compound interest and the simple interest on ₹52500 at 12% per year for 2 years (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹42500 at 4% per year for 2 years (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹58400 at 10% per year for 2 years (in ₹)?
30. 30.A scooter is worth ₹54800. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹36800 at 25% per year for 2 years (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹30000 at 4% per year for 2 years (in ₹)?
33. 33.What amount will ₹24000 grow to in 3 years at 10% per year compound interest (in ₹)?
34. 34.What amount will ₹25900 grow to in 1 year at 8% per year compound interest (in ₹)?
35. 35.What amount will ₹56800 grow to in 1 year at 10% per year compound interest (in ₹)?
36. 36.A town has 7500 people. The population grows by 20% every year. What will the population be after 3 years?
37. 37.A scooter is worth ₹2900. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
38. 38.What is the difference between the compound interest and the simple interest on ₹9100 at 10% per year for 2 years (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹50400 at 5% per year for 2 years (in ₹)?
40. 40.What is the difference between the compound interest and the simple interest on ₹55000 at 8% per year for 2 years (in ₹)?

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