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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 389 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.A town has 33300 people. The population grows by 5% every year. What will the population be after 1 year?
  2. 2.A scooter is worth ₹5000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
  3. 3.What is the difference between the compound interest and the simple interest on ₹38900 at 10% per year for 2 years (in ₹)?
  4. 4.What amount will ₹58000 grow to in 2 years at 5% per year compound interest (in ₹)?
  5. 5.A scooter is worth ₹11300. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  6. 6.A scooter is worth ₹56800. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  7. 7.What amount will ₹52500 grow to in 2 years at 8% per year compound interest (in ₹)?
  8. 8.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
  9. 9.Find the compound interest on ₹39400 at 10% per year for 2 years, compounded every year (in ₹).
  10. 10.A town has 38500 people. The population grows by 20% every year. What will the population be after 3 years?
  11. 11.A scooter is worth ₹2000. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  12. 12.What amount will ₹36000 grow to in 3 years at 20% per year compound interest (in ₹)?
  13. 13.Find the compound interest on ₹49700 at 20% per year for 2 years, compounded every year (in ₹).
  14. 14.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
  15. 15.A town has 40400 people. The population grows by 25% every year. What will the population be after 2 years?
  16. 16.What amount will ₹38000 grow to in 3 years at 10% per year compound interest (in ₹)?
  17. 17.Find the compound interest on ₹59200 at 25% per year for 3 years, compounded every year (in ₹).
  18. 18.A scooter is worth ₹29200. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  19. 19.Find the compound interest on ₹2400 at 5% per year for 2 years, compounded every year (in ₹).
  20. 20.Find the compound interest on ₹32000 at 25% per year for 3 years, compounded every year (in ₹).
  21. 21.A scooter is worth ₹57600. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  22. 22.Find the compound interest on ₹4400 at 10% per year for 1 year, compounded every year (in ₹).
  23. 23.A scooter is worth ₹8000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
  24. 24.What amount will ₹20500 grow to in 3 years at 20% per year compound interest (in ₹)?
  25. 25.A town has 49400 people. The population grows by 12% every year. What will the population be after 1 year?
  26. 26.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
  27. 27.Find the compound interest on ₹59600 at 25% per year for 2 years, compounded every year (in ₹).
  28. 28.A town has 34800 people. The population grows by 25% every year. What will the population be after 2 years?
  29. 29.What amount will ₹2900 grow to in 1 year at 10% per year compound interest (in ₹)?
  30. 30.Find the compound interest on ₹48800 at 5% per year for 2 years, compounded every year (in ₹).
  31. 31.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
  32. 32.What is the difference between the compound interest and the simple interest on ₹15500 at 20% per year for 2 years (in ₹)?
  33. 33.Find the compound interest on ₹15000 at 8% per year for 2 years, compounded every year (in ₹).
  34. 34.What amount will ₹58900 grow to in 1 year at 8% per year compound interest (in ₹)?
  35. 35.A town has 25000 people. The population grows by 8% every year. What will the population be after 2 years?
  36. 36.Find the compound interest on ₹25300 at 20% per year for 2 years, compounded every year (in ₹).
  37. 37.A scooter is worth ₹59600. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  38. 38.What amount will ₹10000 grow to in 2 years at 10% per year compound interest (in ₹)?
  39. 39.What amount will ₹37200 grow to in 2 years at 5% per year compound interest (in ₹)?
  40. 40.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?

Answer key

  1. 34965
  2. 4608
  3. 389
  4. 63945
  5. 10170
  6. 41038
  7. 61236
  8. 18522
  9. 8274
  10. 66528
  11. 1125
  12. 62208
  13. 21868
  14. 64827
  15. 63125
  16. 50578
  17. 56425
  18. 23652
  19. 246
  20. 30500
  21. 54720
  22. 440
  23. 4913
  24. 35424
  25. 55328
  26. 4
  27. 33525
  28. 54375
  29. 3190
  30. 5002
  31. 55566
  32. 620
  33. 2496
  34. 63612
  35. 29160
  36. 11132
  37. 43061
  38. 12100
  39. 41013
  40. 180

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