Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 393 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 34800 people. The population grows by 12% every year. What will the population be after 1 year?
2. 2.What amount will ₹41000 grow to in 3 years at 10% per year compound interest (in ₹)?
3. 3.A town has 50800 people. The population grows by 5% every year. What will the population be after 1 year?
4. 4.What amount will ₹34700 grow to in 2 years at 10% per year compound interest (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹13600 at 20% per year for 2 years (in ₹)?
6. 6.What amount will ₹50000 grow to in 2 years at 12% per year compound interest (in ₹)?
7. 7.A town has 42000 people. The population grows by 10% every year. What will the population be after 3 years?
8. 8.Find the compound interest on ₹19200 at 25% per year for 3 years, compounded every year (in ₹).
9. 9.A town has 20200 people. The population grows by 20% every year. What will the population be after 1 year?
10. 10.A scooter is worth ₹42500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
11. 11.A town has 56000 people. The population grows by 25% every year. What will the population be after 2 years?
12. 12.Find the compound interest on ₹4400 at 5% per year for 2 years, compounded every year (in ₹).
13. 13.What is the difference between the compound interest and the simple interest on ₹51600 at 15% per year for 2 years (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹47200 at 5% per year for 2 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹6400 at 15% per year for 2 years (in ₹)?
16. 16.A scooter is worth ₹5200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
17. 17.Find the compound interest on ₹48000 at 5% per year for 2 years, compounded every year (in ₹).
18. 18.What is the difference between the compound interest and the simple interest on ₹15000 at 4% per year for 2 years (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹44400 at 25% per year for 2 years (in ₹)?
20. 20.A scooter is worth ₹46500. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
21. 21.A scooter is worth ₹20000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
22. 22.What amount will ₹32000 grow to in 2 years at 15% per year compound interest (in ₹)?
23. 23.Find the compound interest on ₹36300 at 20% per year for 2 years, compounded every year (in ₹).
24. 24.Find the compound interest on ₹38000 at 25% per year for 2 years, compounded every year (in ₹).
25. 25.What amount will ₹3900 grow to in 2 years at 10% per year compound interest (in ₹)?
26. 26.A town has 20000 people. The population grows by 25% every year. What will the population be after 2 years?
27. 27.Find the compound interest on ₹27500 at 4% per year for 2 years, compounded every year (in ₹).
28. 28.What is the difference between the compound interest and the simple interest on ₹10000 at 5% per year for 2 years (in ₹)?
29. 29.A scooter is worth ₹2000. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
30. 30.What amount will ₹12000 grow to in 2 years at 15% per year compound interest (in ₹)?
31. 31.What amount will ₹17600 grow to in 2 years at 5% per year compound interest (in ₹)?
32. 32.What amount will ₹27800 grow to in 1 year at 15% per year compound interest (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹57200 at 5% per year for 2 years (in ₹)?
34. 34.Find the compound interest on ₹8700 at 20% per year for 2 years, compounded every year (in ₹).
35. 35.What is the difference between the compound interest and the simple interest on ₹18800 at 15% per year for 2 years (in ₹)?
36. 36.A town has 46700 people. The population grows by 20% every year. What will the population be after 2 years?
37. 37.What amount will ₹13200 grow to in 1 year at 15% per year compound interest (in ₹)?
38. 38.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
39. 39.Find the compound interest on ₹51400 at 15% per year for 1 year, compounded every year (in ₹).
40. 40.Find the compound interest on ₹40100 at 10% per year for 1 year, compounded every year (in ₹).

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