Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What amount will ₹48100 grow to in 1 year at 25% per year compound interest (in ₹)?
- 2.What is the difference between the compound interest and the simple interest on ₹24800 at 15% per year for 2 years (in ₹)?
- 3.What amount will ₹46100 grow to in 1 year at 12% per year compound interest (in ₹)?
- 4.A town has 45000 people. The population grows by 12% every year. What will the population be after 2 years?
- 5.Find the compound interest on ₹50000 at 8% per year for 2 years, compounded every year (in ₹).
- 6.Find the compound interest on ₹57000 at 10% per year for 3 years, compounded every year (in ₹).
- 7.What amount will ₹24000 grow to in 1 year at 4% per year compound interest (in ₹)?
- 8.A scooter is worth ₹57500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 9.A scooter is worth ₹56200. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 10.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 11.Find the compound interest on ₹35600 at 25% per year for 2 years, compounded every year (in ₹).
- 12.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
- 13.What is the difference between the compound interest and the simple interest on ₹13600 at 15% per year for 2 years (in ₹)?
- 14.What amount will ₹12600 grow to in 1 year at 20% per year compound interest (in ₹)?
- 15.Find the compound interest on ₹57200 at 5% per year for 1 year, compounded every year (in ₹).
- 16.A scooter is worth ₹49300. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
- 17.Find the compound interest on ₹3100 at 20% per year for 2 years, compounded every year (in ₹).
- 18.What amount will ₹46900 grow to in 1 year at 8% per year compound interest (in ₹)?
- 19.A town has 30000 people. The population grows by 8% every year. What will the population be after 2 years?
- 20.What is the difference between the compound interest and the simple interest on ₹7100 at 20% per year for 2 years (in ₹)?
- 21.What amount will ₹10000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 22.What amount will ₹16000 grow to in 2 years at 15% per year compound interest (in ₹)?
- 23.Find the compound interest on ₹36000 at 25% per year for 2 years, compounded every year (in ₹).
- 24.What amount will ₹12800 grow to in 1 year at 4% per year compound interest (in ₹)?
- 25.What amount will ₹11800 grow to in 1 year at 5% per year compound interest (in ₹)?
- 26.What is the difference between the compound interest and the simple interest on ₹10400 at 5% per year for 2 years (in ₹)?
- 27.Find the compound interest on ₹30400 at 25% per year for 3 years, compounded every year (in ₹).
- 28.Find the compound interest on ₹17600 at 15% per year for 2 years, compounded every year (in ₹).
- 29.What is the difference between the compound interest and the simple interest on ₹36600 at 10% per year for 2 years (in ₹)?
- 30.A scooter is worth ₹57200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 31.What is the difference between the compound interest and the simple interest on ₹57500 at 8% per year for 2 years (in ₹)?
- 32.A town has 33300 people. The population grows by 20% every year. What will the population be after 1 year?
- 33.A town has 56000 people. The population grows by 15% every year. What will the population be after 3 years?
- 34.Find the compound interest on ₹8000 at 8% per year for 1 year, compounded every year (in ₹).
- 35.What is the difference between the compound interest and the simple interest on ₹32500 at 4% per year for 2 years (in ₹)?
- 36.What amount will ₹3000 grow to in 3 years at 20% per year compound interest (in ₹)?
- 37.Find the compound interest on ₹6400 at 20% per year for 1 year, compounded every year (in ₹).
- 38.What is the difference between the compound interest and the simple interest on ₹42400 at 25% per year for 2 years (in ₹)?
- 39.Find the compound interest on ₹11600 at 5% per year for 1 year, compounded every year (in ₹).
- 40.What amount will ₹52000 grow to in 3 years at 10% per year compound interest (in ₹)?
Answer key
- 60125
- 558
- 51632
- 56448
- 8320
- 18867
- 24960
- 48668
- 47770
- 27783
- 20025
- 25002
- 306
- 15120
- 2860
- 31552
- 1364
- 50652
- 34992
- 284
- 13310
- 21160
- 20250
- 13312
- 12390
- 26
- 28975
- 5676
- 366
- 51623
- 368
- 39960
- 85169
- 640
- 52
- 5184
- 1280
- 2650
- 580
- 69212
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