Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 40 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 23200 people. The population grows by 5% every year. What will the population be after 1 year?
2. 2.Find the compound interest on ₹7000 at 10% per year for 2 years, compounded every year (in ₹).
3. 3.Find the compound interest on ₹23900 at 8% per year for 1 year, compounded every year (in ₹).
4. 4.Find the compound interest on ₹40200 at 15% per year for 1 year, compounded every year (in ₹).
5. 5.What is the difference between the compound interest and the simple interest on ₹40800 at 5% per year for 2 years (in ₹)?
6. 6.What amount will ₹56000 grow to in 3 years at 25% per year compound interest (in ₹)?
7. 7.Find the compound interest on ₹33600 at 10% per year for 1 year, compounded every year (in ₹).
8. 8.Find the compound interest on ₹21600 at 25% per year for 2 years, compounded every year (in ₹).
9. 9.A scooter is worth ₹40500. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹18000 at 5% per year for 2 years (in ₹)?
11. 11.A town has 24000 people. The population grows by 5% every year. What will the population be after 3 years?
12. 12.A scooter is worth ₹37500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹7500 at 8% per year for 2 years (in ₹)?
14. 14.Find the compound interest on ₹15200 at 5% per year for 2 years, compounded every year (in ₹).
15. 15.Find the compound interest on ₹41100 at 10% per year for 1 year, compounded every year (in ₹).
16. 16.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
17. 17.Find the compound interest on ₹2000 at 10% per year for 3 years, compounded every year (in ₹).
18. 18.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
19. 19.A scooter is worth ₹18100. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹8600 at 10% per year for 2 years (in ₹)?
21. 21.Find the compound interest on ₹35600 at 10% per year for 2 years, compounded every year (in ₹).
22. 22.A scooter is worth ₹25200. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
23. 23.A town has 22700 people. The population grows by 5% every year. What will the population be after 1 year?
24. 24.What is the difference between the compound interest and the simple interest on ₹52700 at 10% per year for 2 years (in ₹)?
25. 25.Find the compound interest on ₹55000 at 8% per year for 2 years, compounded every year (in ₹).
26. 26.A town has 57400 people. The population grows by 8% every year. What will the population be after 1 year?
27. 27.What amount will ₹40600 grow to in 1 year at 20% per year compound interest (in ₹)?
28. 28.A town has 14400 people. The population grows by 25% every year. What will the population be after 2 years?
29. 29.What is the difference between the compound interest and the simple interest on ₹38700 at 10% per year for 2 years (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹54600 at 20% per year for 2 years (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹40700 at 20% per year for 2 years (in ₹)?
32. 32.A scooter is worth ₹27500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
33. 33.What amount will ₹42500 grow to in 2 years at 8% per year compound interest (in ₹)?
34. 34.What amount will ₹35000 grow to in 2 years at 8% per year compound interest (in ₹)?
35. 35.A town has 35400 people. The population grows by 4% every year. What will the population be after 1 year?
36. 36.A town has 11700 people. The population grows by 25% every year. What will the population be after 1 year?
37. 37.Find the compound interest on ₹20600 at 10% per year for 2 years, compounded every year (in ₹).
38. 38.What amount will ₹30400 grow to in 1 year at 12% per year compound interest (in ₹)?
39. 39.Find the compound interest on ₹5000 at 8% per year for 2 years, compounded every year (in ₹).
40. 40.What amount will ₹5300 grow to in 1 year at 20% per year compound interest (in ₹)?

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