Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 401 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹9200 at 4% per year for 1 year, compounded every year (in ₹).
2. 2.What is the difference between the compound interest and the simple interest on ₹16600 at 10% per year for 2 years (in ₹)?
3. 3.What amount will ₹21200 grow to in 2 years at 25% per year compound interest (in ₹)?
4. 4.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
5. 5.Find the compound interest on ₹15000 at 4% per year for 2 years, compounded every year (in ₹).
6. 6.Find the compound interest on ₹9700 at 25% per year for 1 year, compounded every year (in ₹).
7. 7.Find the compound interest on ₹4000 at 20% per year for 1 year, compounded every year (in ₹).
8. 8.What amount will ₹29000 grow to in 3 years at 10% per year compound interest (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹5000 at 4% per year for 2 years (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹32000 at 15% per year for 2 years (in ₹)?
11. 11.Find the compound interest on ₹10000 at 4% per year for 2 years, compounded every year (in ₹).
12. 12.Find the compound interest on ₹7300 at 8% per year for 1 year, compounded every year (in ₹).
13. 13.A town has 5000 people. The population grows by 20% every year. What will the population be after 3 years?
14. 14.What is the difference between the compound interest and the simple interest on ₹10400 at 15% per year for 2 years (in ₹)?
15. 15.Find the compound interest on ₹42500 at 5% per year for 1 year, compounded every year (in ₹).
16. 16.Find the compound interest on ₹5300 at 8% per year for 1 year, compounded every year (in ₹).
17. 17.Find the compound interest on ₹47500 at 20% per year for 3 years, compounded every year (in ₹).
18. 18.What is the difference between the compound interest and the simple interest on ₹16300 at 20% per year for 2 years (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹50400 at 15% per year for 2 years (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹51600 at 15% per year for 2 years (in ₹)?
21. 21.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
22. 22.Find the compound interest on ₹19200 at 25% per year for 3 years, compounded every year (in ₹).
23. 23.What amount will ₹57400 grow to in 1 year at 4% per year compound interest (in ₹)?
24. 24.Find the compound interest on ₹26900 at 10% per year for 2 years, compounded every year (in ₹).
25. 25.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
26. 26.Find the compound interest on ₹7500 at 4% per year for 2 years, compounded every year (in ₹).
27. 27.A town has 12000 people. The population grows by 10% every year. What will the population be after 3 years?
28. 28.What amount will ₹8000 grow to in 3 years at 10% per year compound interest (in ₹)?
29. 29.What amount will ₹25300 grow to in 1 year at 4% per year compound interest (in ₹)?
30. 30.What amount will ₹7000 grow to in 3 years at 10% per year compound interest (in ₹)?
31. 31.A scooter is worth ₹41500. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
32. 32.A town has 17500 people. The population grows by 4% every year. What will the population be after 2 years?
33. 33.What amount will ₹58600 grow to in 1 year at 25% per year compound interest (in ₹)?
34. 34.What amount will ₹56000 grow to in 3 years at 15% per year compound interest (in ₹)?
35. 35.What amount will ₹10100 grow to in 1 year at 15% per year compound interest (in ₹)?
36. 36.A town has 15900 people. The population grows by 5% every year. What will the population be after 1 year?
37. 37.What amount will ₹10000 grow to in 2 years at 4% per year compound interest (in ₹)?
38. 38.Find the compound interest on ₹53400 at 5% per year for 1 year, compounded every year (in ₹).
39. 39.What amount will ₹2000 grow to in 2 years at 15% per year compound interest (in ₹)?
40. 40.Find the compound interest on ₹57900 at 12% per year for 1 year, compounded every year (in ₹).

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