Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A town has 26000 people. The population grows by 5% every year. What will the population be after 2 years?
- 2.What amount will ₹46400 grow to in 3 years at 25% per year compound interest (in ₹)?
- 3.A scooter is worth ₹58900. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 4.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
- 5.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
- 6.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 7.A scooter is worth ₹30700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 8.A town has 8800 people. The population grows by 25% every year. What will the population be after 2 years?
- 9.A scooter is worth ₹17200. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 10.A town has 31000 people. The population grows by 10% every year. What will the population be after 1 year?
- 11.Find the compound interest on ₹28600 at 10% per year for 1 year, compounded every year (in ₹).
- 12.A scooter is worth ₹33700. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 13.Find the compound interest on ₹55600 at 12% per year for 1 year, compounded every year (in ₹).
- 14.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?
- 15.What amount will ₹59200 grow to in 3 years at 25% per year compound interest (in ₹)?
- 16.What amount will ₹33600 grow to in 2 years at 25% per year compound interest (in ₹)?
- 17.Find the compound interest on ₹17600 at 10% per year for 1 year, compounded every year (in ₹).
- 18.Find the compound interest on ₹51300 at 10% per year for 2 years, compounded every year (in ₹).
- 19.Find the compound interest on ₹43200 at 5% per year for 2 years, compounded every year (in ₹).
- 20.What is the difference between the compound interest and the simple interest on ₹27000 at 20% per year for 2 years (in ₹)?
- 21.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
- 22.Find the compound interest on ₹3000 at 20% per year for 3 years, compounded every year (in ₹).
- 23.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?
- 24.A town has 5000 people. The population grows by 8% every year. What will the population be after 2 years?
- 25.A town has 38000 people. The population grows by 10% every year. What will the population be after 3 years?
- 26.What amount will ₹17500 grow to in 1 year at 5% per year compound interest (in ₹)?
- 27.A scooter is worth ₹17000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 28.Find the compound interest on ₹6300 at 10% per year for 2 years, compounded every year (in ₹).
- 29.Find the compound interest on ₹2000 at 25% per year for 2 years, compounded every year (in ₹).
- 30.What is the difference between the compound interest and the simple interest on ₹15000 at 20% per year for 2 years (in ₹)?
- 31.What is the difference between the compound interest and the simple interest on ₹22500 at 8% per year for 2 years (in ₹)?
- 32.A scooter is worth ₹17500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
- 33.What amount will ₹16000 grow to in 3 years at 25% per year compound interest (in ₹)?
- 34.What is the difference between the compound interest and the simple interest on ₹6100 at 10% per year for 2 years (in ₹)?
- 35.Find the compound interest on ₹13200 at 15% per year for 2 years, compounded every year (in ₹).
- 36.A town has 5600 people. The population grows by 4% every year. What will the population be after 1 year?
- 37.What is the difference between the compound interest and the simple interest on ₹41600 at 5% per year for 2 years (in ₹)?
- 38.A scooter is worth ₹24000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 39.What is the difference between the compound interest and the simple interest on ₹44800 at 25% per year for 2 years (in ₹)?
- 40.A town has 2000 people. The population grows by 10% every year. What will the population be after 3 years?
Answer key
- 28665
- 90625
- 47709
- 112
- 3783
- 18522
- 27630
- 13750
- 9675
- 34100
- 2860
- 28645
- 6672
- 20
- 115625
- 52500
- 1760
- 10773
- 4428
- 1080
- 864
- 2184
- 144
- 5832
- 50578
- 18375
- 8704
- 1323
- 1125
- 600
- 144
- 13552
- 31250
- 61
- 4257
- 5824
- 104
- 20577
- 2800
- 2662
Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets