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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 404 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.A town has 26000 people. The population grows by 5% every year. What will the population be after 2 years?
  2. 2.What amount will ₹46400 grow to in 3 years at 25% per year compound interest (in ₹)?
  3. 3.A scooter is worth ₹58900. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
  5. 5.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
  6. 6.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
  7. 7.A scooter is worth ₹30700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  8. 8.A town has 8800 people. The population grows by 25% every year. What will the population be after 2 years?
  9. 9.A scooter is worth ₹17200. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  10. 10.A town has 31000 people. The population grows by 10% every year. What will the population be after 1 year?
  11. 11.Find the compound interest on ₹28600 at 10% per year for 1 year, compounded every year (in ₹).
  12. 12.A scooter is worth ₹33700. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
  13. 13.Find the compound interest on ₹55600 at 12% per year for 1 year, compounded every year (in ₹).
  14. 14.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?
  15. 15.What amount will ₹59200 grow to in 3 years at 25% per year compound interest (in ₹)?
  16. 16.What amount will ₹33600 grow to in 2 years at 25% per year compound interest (in ₹)?
  17. 17.Find the compound interest on ₹17600 at 10% per year for 1 year, compounded every year (in ₹).
  18. 18.Find the compound interest on ₹51300 at 10% per year for 2 years, compounded every year (in ₹).
  19. 19.Find the compound interest on ₹43200 at 5% per year for 2 years, compounded every year (in ₹).
  20. 20.What is the difference between the compound interest and the simple interest on ₹27000 at 20% per year for 2 years (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
  22. 22.Find the compound interest on ₹3000 at 20% per year for 3 years, compounded every year (in ₹).
  23. 23.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?
  24. 24.A town has 5000 people. The population grows by 8% every year. What will the population be after 2 years?
  25. 25.A town has 38000 people. The population grows by 10% every year. What will the population be after 3 years?
  26. 26.What amount will ₹17500 grow to in 1 year at 5% per year compound interest (in ₹)?
  27. 27.A scooter is worth ₹17000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
  28. 28.Find the compound interest on ₹6300 at 10% per year for 2 years, compounded every year (in ₹).
  29. 29.Find the compound interest on ₹2000 at 25% per year for 2 years, compounded every year (in ₹).
  30. 30.What is the difference between the compound interest and the simple interest on ₹15000 at 20% per year for 2 years (in ₹)?
  31. 31.What is the difference between the compound interest and the simple interest on ₹22500 at 8% per year for 2 years (in ₹)?
  32. 32.A scooter is worth ₹17500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  33. 33.What amount will ₹16000 grow to in 3 years at 25% per year compound interest (in ₹)?
  34. 34.What is the difference between the compound interest and the simple interest on ₹6100 at 10% per year for 2 years (in ₹)?
  35. 35.Find the compound interest on ₹13200 at 15% per year for 2 years, compounded every year (in ₹).
  36. 36.A town has 5600 people. The population grows by 4% every year. What will the population be after 1 year?
  37. 37.What is the difference between the compound interest and the simple interest on ₹41600 at 5% per year for 2 years (in ₹)?
  38. 38.A scooter is worth ₹24000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  39. 39.What is the difference between the compound interest and the simple interest on ₹44800 at 25% per year for 2 years (in ₹)?
  40. 40.A town has 2000 people. The population grows by 10% every year. What will the population be after 3 years?

Answer key

  1. 28665
  2. 90625
  3. 47709
  4. 112
  5. 3783
  6. 18522
  7. 27630
  8. 13750
  9. 9675
  10. 34100
  11. 2860
  12. 28645
  13. 6672
  14. 20
  15. 115625
  16. 52500
  17. 1760
  18. 10773
  19. 4428
  20. 1080
  21. 864
  22. 2184
  23. 144
  24. 5832
  25. 50578
  26. 18375
  27. 8704
  28. 1323
  29. 1125
  30. 600
  31. 144
  32. 13552
  33. 31250
  34. 61
  35. 4257
  36. 5824
  37. 104
  38. 20577
  39. 2800
  40. 2662

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