Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 411 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹25000 at 4% per year for 1 year, compounded every year (in ₹).
2. 2.Find the compound interest on ₹32000 at 5% per year for 2 years, compounded every year (in ₹).
3. 3.Find the compound interest on ₹15000 at 8% per year for 2 years, compounded every year (in ₹).
4. 4.What is the difference between the compound interest and the simple interest on ₹40000 at 4% per year for 2 years (in ₹)?
5. 5.A town has 44000 people. The population grows by 15% every year. What will the population be after 2 years?
6. 6.A scooter is worth ₹2000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
7. 7.A town has 45900 people. The population grows by 20% every year. What will the population be after 1 year?
8. 8.What is the difference between the compound interest and the simple interest on ₹4400 at 10% per year for 2 years (in ₹)?
9. 9.A town has 8100 people. The population grows by 10% every year. What will the population be after 1 year?
10. 10.What is the difference between the compound interest and the simple interest on ₹33900 at 20% per year for 2 years (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹55600 at 15% per year for 2 years (in ₹)?
13. 13.Find the compound interest on ₹30400 at 10% per year for 1 year, compounded every year (in ₹).
14. 14.What amount will ₹28200 grow to in 1 year at 15% per year compound interest (in ₹)?
15. 15.Find the compound interest on ₹50200 at 10% per year for 2 years, compounded every year (in ₹).
16. 16.What amount will ₹32000 grow to in 3 years at 10% per year compound interest (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹37500 at 8% per year for 2 years (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
19. 19.What amount will ₹24400 grow to in 1 year at 12% per year compound interest (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹18000 at 10% per year for 2 years (in ₹)?
21. 21.What amount will ₹51300 grow to in 2 years at 10% per year compound interest (in ₹)?
22. 22.What amount will ₹36800 grow to in 1 year at 5% per year compound interest (in ₹)?
23. 23.What amount will ₹2800 grow to in 1 year at 12% per year compound interest (in ₹)?
24. 24.Find the compound interest on ₹41300 at 8% per year for 1 year, compounded every year (in ₹).
25. 25.A scooter is worth ₹8000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹32300 at 10% per year for 2 years (in ₹)?
27. 27.Find the compound interest on ₹7000 at 20% per year for 3 years, compounded every year (in ₹).
28. 28.Find the compound interest on ₹14800 at 15% per year for 2 years, compounded every year (in ₹).
29. 29.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
30. 30.A town has 43800 people. The population grows by 5% every year. What will the population be after 1 year?
31. 31.Find the compound interest on ₹49800 at 10% per year for 1 year, compounded every year (in ₹).
32. 32.What amount will ₹33400 grow to in 1 year at 5% per year compound interest (in ₹)?
33. 33.A town has 25500 people. The population grows by 8% every year. What will the population be after 1 year?
34. 34.Find the compound interest on ₹14700 at 4% per year for 1 year, compounded every year (in ₹).
35. 35.Find the compound interest on ₹6000 at 25% per year for 2 years, compounded every year (in ₹).
36. 36.Find the compound interest on ₹9200 at 12% per year for 1 year, compounded every year (in ₹).
37. 37.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
38. 38.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
39. 39.A town has 7500 people. The population grows by 12% every year. What will the population be after 2 years?
40. 40.What is the difference between the compound interest and the simple interest on ₹30000 at 4% per year for 2 years (in ₹)?

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