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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 421 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.A town has 59200 people. The population grows by 5% every year. What will the population be after 2 years?
  2. 2.A town has 28600 people. The population grows by 20% every year. What will the population be after 2 years?
  3. 3.A scooter is worth ₹8000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹16500 at 20% per year for 2 years (in ₹)?
  5. 5.A town has 24400 people. The population grows by 25% every year. What will the population be after 1 year?
  6. 6.What is the difference between the compound interest and the simple interest on ₹55000 at 12% per year for 2 years (in ₹)?
  7. 7.A town has 3000 people. The population grows by 20% every year. What will the population be after 2 years?
  8. 8.A scooter is worth ₹47600. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  9. 9.Find the compound interest on ₹49200 at 15% per year for 2 years, compounded every year (in ₹).
  10. 10.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
  11. 11.A scooter is worth ₹56000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
  12. 12.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
  13. 13.Find the compound interest on ₹45200 at 25% per year for 2 years, compounded every year (in ₹).
  14. 14.Find the compound interest on ₹31200 at 20% per year for 1 year, compounded every year (in ₹).
  15. 15.What amount will ₹59200 grow to in 2 years at 5% per year compound interest (in ₹)?
  16. 16.Find the compound interest on ₹5200 at 15% per year for 2 years, compounded every year (in ₹).
  17. 17.What is the difference between the compound interest and the simple interest on ₹37500 at 12% per year for 2 years (in ₹)?
  18. 18.What is the difference between the compound interest and the simple interest on ₹17600 at 5% per year for 2 years (in ₹)?
  19. 19.What is the difference between the compound interest and the simple interest on ₹34000 at 15% per year for 2 years (in ₹)?
  20. 20.A scooter is worth ₹37000. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹8400 at 25% per year for 2 years (in ₹)?
  22. 22.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
  23. 23.What amount will ₹7500 grow to in 2 years at 4% per year compound interest (in ₹)?
  24. 24.What is the difference between the compound interest and the simple interest on ₹15000 at 12% per year for 2 years (in ₹)?
  25. 25.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
  26. 26.What is the difference between the compound interest and the simple interest on ₹14900 at 20% per year for 2 years (in ₹)?
  27. 27.What amount will ₹45900 grow to in 1 year at 25% per year compound interest (in ₹)?
  28. 28.Find the compound interest on ₹12900 at 25% per year for 1 year, compounded every year (in ₹).
  29. 29.What amount will ₹24000 grow to in 3 years at 15% per year compound interest (in ₹)?
  30. 30.Find the compound interest on ₹32000 at 5% per year for 2 years, compounded every year (in ₹).
  31. 31.Find the compound interest on ₹35000 at 4% per year for 2 years, compounded every year (in ₹).
  32. 32.What amount will ₹57900 grow to in 1 year at 4% per year compound interest (in ₹)?
  33. 33.Find the compound interest on ₹49600 at 25% per year for 2 years, compounded every year (in ₹).
  34. 34.A town has 21000 people. The population grows by 10% every year. What will the population be after 3 years?
  35. 35.A town has 8100 people. The population grows by 4% every year. What will the population be after 1 year?
  36. 36.Find the compound interest on ₹9000 at 8% per year for 1 year, compounded every year (in ₹).
  37. 37.What is the difference between the compound interest and the simple interest on ₹44800 at 15% per year for 2 years (in ₹)?
  38. 38.Find the compound interest on ₹40400 at 15% per year for 2 years, compounded every year (in ₹).
  39. 39.Find the compound interest on ₹9800 at 4% per year for 1 year, compounded every year (in ₹).
  40. 40.Find the compound interest on ₹51700 at 4% per year for 1 year, compounded every year (in ₹).

Answer key

  1. 65268
  2. 41184
  3. 6859
  4. 660
  5. 30500
  6. 792
  7. 4320
  8. 26775
  9. 15867
  10. 9261
  11. 34391
  12. 55566
  13. 25425
  14. 6240
  15. 65268
  16. 1677
  17. 540
  18. 44
  19. 765
  20. 34040
  21. 525
  22. 16
  23. 8112
  24. 216
  25. 20835
  26. 596
  27. 57375
  28. 3225
  29. 36501
  30. 3280
  31. 2856
  32. 60216
  33. 27900
  34. 27951
  35. 8424
  36. 720
  37. 1008
  38. 13029
  39. 392
  40. 2068

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