Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 424 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 11300 people. The population grows by 20% every year. What will the population be after 2 years?
2. 2.Find the compound interest on ₹53600 at 15% per year for 1 year, compounded every year (in ₹).
3. 3.What is the difference between the compound interest and the simple interest on ₹50800 at 15% per year for 2 years (in ₹)?
4. 4.What amount will ₹24000 grow to in 3 years at 15% per year compound interest (in ₹)?
5. 5.A town has 12500 people. The population grows by 12% every year. What will the population be after 2 years?
6. 6.What is the difference between the compound interest and the simple interest on ₹4400 at 15% per year for 2 years (in ₹)?
7. 7.A scooter is worth ₹40800. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
8. 8.What amount will ₹32900 grow to in 1 year at 4% per year compound interest (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹56400 at 5% per year for 2 years (in ₹)?
10. 10.A scooter is worth ₹2000. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
11. 11.What amount will ₹54400 grow to in 3 years at 25% per year compound interest (in ₹)?
12. 12.What amount will ₹8400 grow to in 1 year at 8% per year compound interest (in ₹)?
13. 13.What amount will ₹4100 grow to in 1 year at 5% per year compound interest (in ₹)?
14. 14.Find the compound interest on ₹17300 at 8% per year for 1 year, compounded every year (in ₹).
15. 15.Find the compound interest on ₹17600 at 25% per year for 3 years, compounded every year (in ₹).
16. 16.Find the compound interest on ₹52400 at 5% per year for 2 years, compounded every year (in ₹).
17. 17.What amount will ₹31100 grow to in 2 years at 10% per year compound interest (in ₹)?
18. 18.What amount will ₹60000 grow to in 2 years at 12% per year compound interest (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹58000 at 20% per year for 2 years (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹48100 at 10% per year for 2 years (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹26400 at 5% per year for 2 years (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹12800 at 5% per year for 2 years (in ₹)?
23. 23.Find the compound interest on ₹36500 at 20% per year for 3 years, compounded every year (in ₹).
24. 24.A town has 7500 people. The population grows by 4% every year. What will the population be after 2 years?
25. 25.Find the compound interest on ₹53700 at 12% per year for 1 year, compounded every year (in ₹).
26. 26.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
27. 27.A town has 9800 people. The population grows by 25% every year. What will the population be after 1 year?
28. 28.A town has 35000 people. The population grows by 12% every year. What will the population be after 2 years?
29. 29.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
30. 30.A town has 12400 people. The population grows by 10% every year. What will the population be after 2 years?
31. 31.A scooter is worth ₹51300. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
32. 32.Find the compound interest on ₹14400 at 25% per year for 3 years, compounded every year (in ₹).
33. 33.A town has 48000 people. The population grows by 15% every year. What will the population be after 3 years?
34. 34.A scooter is worth ₹6400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
35. 35.What amount will ₹1600 grow to in 3 years at 25% per year compound interest (in ₹)?
36. 36.A scooter is worth ₹5100. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
37. 37.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
38. 38.What is the difference between the compound interest and the simple interest on ₹8800 at 5% per year for 2 years (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹34800 at 25% per year for 2 years (in ₹)?
40. 40.Find the compound interest on ₹34800 at 25% per year for 2 years, compounded every year (in ₹).

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