Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 43 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹32500 grow to in 1 year at 12% per year compound interest (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹40000 at 5% per year for 2 years (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹30100 at 20% per year for 2 years (in ₹)?
4. 4.Find the compound interest on ₹33600 at 5% per year for 2 years, compounded every year (in ₹).
5. 5.Find the compound interest on ₹48500 at 20% per year for 3 years, compounded every year (in ₹).
6. 6.What is the difference between the compound interest and the simple interest on ₹38800 at 5% per year for 2 years (in ₹)?
7. 7.A scooter is worth ₹48800. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
8. 8.Find the compound interest on ₹24900 at 25% per year for 1 year, compounded every year (in ₹).
9. 9.What amount will ₹42800 grow to in 2 years at 25% per year compound interest (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹54000 at 15% per year for 2 years (in ₹)?
11. 11.Find the compound interest on ₹18400 at 5% per year for 1 year, compounded every year (in ₹).
12. 12.Find the compound interest on ₹55300 at 10% per year for 2 years, compounded every year (in ₹).
13. 13.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
14. 14.What is the difference between the compound interest and the simple interest on ₹52500 at 12% per year for 2 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹47500 at 12% per year for 2 years (in ₹)?
17. 17.A scooter is worth ₹15900. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
18. 18.What amount will ₹30100 grow to in 1 year at 25% per year compound interest (in ₹)?
19. 19.Find the compound interest on ₹50400 at 20% per year for 1 year, compounded every year (in ₹).
20. 20.A town has 36000 people. The population grows by 10% every year. What will the population be after 3 years?
21. 21.A town has 5600 people. The population grows by 5% every year. What will the population be after 2 years?
22. 22.What is the difference between the compound interest and the simple interest on ₹3600 at 5% per year for 2 years (in ₹)?
23. 23.A town has 42000 people. The population grows by 10% every year. What will the population be after 3 years?
24. 24.A town has 1600 people. The population grows by 25% every year. What will the population be after 3 years?
25. 25.What amount will ₹20700 grow to in 1 year at 10% per year compound interest (in ₹)?
26. 26.Find the compound interest on ₹29500 at 20% per year for 3 years, compounded every year (in ₹).
27. 27.A town has 8700 people. The population grows by 15% every year. What will the population be after 1 year?
28. 28.What is the difference between the compound interest and the simple interest on ₹55000 at 12% per year for 2 years (in ₹)?
29. 29.A town has 59500 people. The population grows by 25% every year. What will the population be after 1 year?
30. 30.Find the compound interest on ₹27900 at 15% per year for 1 year, compounded every year (in ₹).
31. 31.A scooter is worth ₹51900. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
32. 32.What amount will ₹9100 grow to in 1 year at 12% per year compound interest (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹38400 at 15% per year for 2 years (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹24800 at 15% per year for 2 years (in ₹)?
35. 35.What amount will ₹37900 grow to in 2 years at 10% per year compound interest (in ₹)?
36. 36.A town has 27200 people. The population grows by 15% every year. What will the population be after 2 years?
37. 37.Find the compound interest on ₹17300 at 20% per year for 2 years, compounded every year (in ₹).
38. 38.Find the compound interest on ₹22500 at 4% per year for 2 years, compounded every year (in ₹).
39. 39.What amount will ₹29800 grow to in 1 year at 12% per year compound interest (in ₹)?
40. 40.A town has 3000 people. The population grows by 8% every year. What will the population be after 1 year?

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