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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 431 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.Find the compound interest on ₹44500 at 15% per year for 1 year, compounded every year (in ₹).
  2. 2.A scooter is worth ₹50100. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
  3. 3.What is the difference between the compound interest and the simple interest on ₹6200 at 10% per year for 2 years (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?
  5. 5.What amount will ₹34000 grow to in 3 years at 10% per year compound interest (in ₹)?
  6. 6.Find the compound interest on ₹48000 at 25% per year for 3 years, compounded every year (in ₹).
  7. 7.A town has 10700 people. The population grows by 12% every year. What will the population be after 1 year?
  8. 8.What amount will ₹52500 grow to in 2 years at 12% per year compound interest (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹20000 at 25% per year for 2 years (in ₹)?
  10. 10.What amount will ₹22500 grow to in 2 years at 8% per year compound interest (in ₹)?
  11. 11.Find the compound interest on ₹24200 at 12% per year for 1 year, compounded every year (in ₹).
  12. 12.Find the compound interest on ₹22500 at 4% per year for 2 years, compounded every year (in ₹).
  13. 13.Find the compound interest on ₹24000 at 10% per year for 3 years, compounded every year (in ₹).
  14. 14.A town has 58000 people. The population grows by 10% every year. What will the population be after 3 years?
  15. 15.A town has 32500 people. The population grows by 12% every year. What will the population be after 2 years?
  16. 16.A town has 8000 people. The population grows by 25% every year. What will the population be after 3 years?
  17. 17.A scooter is worth ₹48000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  18. 18.Find the compound interest on ₹40300 at 10% per year for 1 year, compounded every year (in ₹).
  19. 19.What is the difference between the compound interest and the simple interest on ₹55600 at 25% per year for 2 years (in ₹)?
  20. 20.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
  21. 21.A scooter is worth ₹7600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  22. 22.A town has 52500 people. The population grows by 20% every year. What will the population be after 1 year?
  23. 23.Find the compound interest on ₹12000 at 10% per year for 3 years, compounded every year (in ₹).
  24. 24.Find the compound interest on ₹20500 at 20% per year for 3 years, compounded every year (in ₹).
  25. 25.Find the compound interest on ₹16900 at 8% per year for 1 year, compounded every year (in ₹).
  26. 26.What amount will ₹29300 grow to in 1 year at 20% per year compound interest (in ₹)?
  27. 27.What amount will ₹52700 grow to in 1 year at 10% per year compound interest (in ₹)?
  28. 28.What is the difference between the compound interest and the simple interest on ₹53400 at 10% per year for 2 years (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹49600 at 15% per year for 2 years (in ₹)?
  30. 30.What amount will ₹13200 grow to in 2 years at 15% per year compound interest (in ₹)?
  31. 31.What amount will ₹17500 grow to in 2 years at 8% per year compound interest (in ₹)?
  32. 32.What is the difference between the compound interest and the simple interest on ₹16400 at 25% per year for 2 years (in ₹)?
  33. 33.What is the difference between the compound interest and the simple interest on ₹3600 at 5% per year for 2 years (in ₹)?
  34. 34.Find the compound interest on ₹27500 at 20% per year for 3 years, compounded every year (in ₹).
  35. 35.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
  36. 36.A town has 3000 people. The population grows by 10% every year. What will the population be after 3 years?
  37. 37.What amount will ₹18000 grow to in 2 years at 15% per year compound interest (in ₹)?
  38. 38.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
  39. 39.What is the difference between the compound interest and the simple interest on ₹55000 at 4% per year for 2 years (in ₹)?
  40. 40.A town has 37000 people. The population grows by 15% every year. What will the population be after 1 year?

Answer key

  1. 6675
  2. 32064
  3. 62
  4. 504
  5. 45254
  6. 45750
  7. 11984
  8. 65856
  9. 1250
  10. 26244
  11. 2904
  12. 1836
  13. 7944
  14. 77198
  15. 40768
  16. 15625
  17. 34992
  18. 4030
  19. 3475
  20. 2522
  21. 6859
  22. 63000
  23. 3972
  24. 14924
  25. 1352
  26. 35160
  27. 57970
  28. 534
  29. 1116
  30. 17457
  31. 20412
  32. 1025
  33. 9
  34. 20020
  35. 27783
  36. 3993
  37. 23805
  38. 384
  39. 88
  40. 42550

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