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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 434 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹16200 at 10% per year for 2 years (in ₹)?
  2. 2.What is the difference between the compound interest and the simple interest on ₹7500 at 8% per year for 2 years (in ₹)?
  3. 3.What amount will ₹34500 grow to in 1 year at 20% per year compound interest (in ₹)?
  4. 4.A town has 11400 people. The population grows by 5% every year. What will the population be after 1 year?
  5. 5.Find the compound interest on ₹46500 at 25% per year for 1 year, compounded every year (in ₹).
  6. 6.Find the compound interest on ₹27100 at 12% per year for 1 year, compounded every year (in ₹).
  7. 7.Find the compound interest on ₹27900 at 10% per year for 1 year, compounded every year (in ₹).
  8. 8.What is the difference between the compound interest and the simple interest on ₹42500 at 8% per year for 2 years (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹2000 at 5% per year for 2 years (in ₹)?
  10. 10.Find the compound interest on ₹26800 at 5% per year for 2 years, compounded every year (in ₹).
  11. 11.Find the compound interest on ₹31600 at 15% per year for 2 years, compounded every year (in ₹).
  12. 12.What is the difference between the compound interest and the simple interest on ₹6800 at 10% per year for 2 years (in ₹)?
  13. 13.A town has 12800 people. The population grows by 25% every year. What will the population be after 3 years?
  14. 14.Find the compound interest on ₹52500 at 8% per year for 2 years, compounded every year (in ₹).
  15. 15.A town has 51000 people. The population grows by 10% every year. What will the population be after 3 years?
  16. 16.A town has 56000 people. The population grows by 5% every year. What will the population be after 3 years?
  17. 17.What is the difference between the compound interest and the simple interest on ₹58000 at 25% per year for 2 years (in ₹)?
  18. 18.A scooter is worth ₹58000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
  19. 19.What is the difference between the compound interest and the simple interest on ₹32500 at 10% per year for 2 years (in ₹)?
  20. 20.What is the difference between the compound interest and the simple interest on ₹58400 at 25% per year for 2 years (in ₹)?
  21. 21.Find the compound interest on ₹10500 at 20% per year for 3 years, compounded every year (in ₹).
  22. 22.Find the compound interest on ₹22000 at 5% per year for 2 years, compounded every year (in ₹).
  23. 23.What is the difference between the compound interest and the simple interest on ₹13800 at 20% per year for 2 years (in ₹)?
  24. 24.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
  25. 25.What is the difference between the compound interest and the simple interest on ₹14800 at 15% per year for 2 years (in ₹)?
  26. 26.Find the compound interest on ₹12800 at 15% per year for 2 years, compounded every year (in ₹).
  27. 27.A town has 34000 people. The population grows by 20% every year. What will the population be after 2 years?
  28. 28.Find the compound interest on ₹20000 at 12% per year for 1 year, compounded every year (in ₹).
  29. 29.Find the compound interest on ₹42500 at 4% per year for 2 years, compounded every year (in ₹).
  30. 30.What amount will ₹11600 grow to in 1 year at 15% per year compound interest (in ₹)?
  31. 31.What amount will ₹44000 grow to in 1 year at 10% per year compound interest (in ₹)?
  32. 32.What amount will ₹28000 grow to in 2 years at 25% per year compound interest (in ₹)?
  33. 33.A scooter is worth ₹12000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  34. 34.What is the difference between the compound interest and the simple interest on ₹22800 at 25% per year for 2 years (in ₹)?
  35. 35.What is the difference between the compound interest and the simple interest on ₹18800 at 15% per year for 2 years (in ₹)?
  36. 36.A town has 39400 people. The population grows by 25% every year. What will the population be after 1 year?
  37. 37.Find the compound interest on ₹48000 at 10% per year for 3 years, compounded every year (in ₹).
  38. 38.What is the difference between the compound interest and the simple interest on ₹52500 at 12% per year for 2 years (in ₹)?
  39. 39.Find the compound interest on ₹13900 at 10% per year for 1 year, compounded every year (in ₹).
  40. 40.What amount will ₹19800 grow to in 1 year at 4% per year compound interest (in ₹)?

Answer key

  1. 162
  2. 48
  3. 41400
  4. 11970
  5. 11625
  6. 3252
  7. 2790
  8. 272
  9. 5
  10. 2747
  11. 10191
  12. 68
  13. 25000
  14. 8736
  15. 67881
  16. 64827
  17. 3625
  18. 29696
  19. 325
  20. 3650
  21. 7644
  22. 2255
  23. 552
  24. 72
  25. 333
  26. 4128
  27. 48960
  28. 2400
  29. 3468
  30. 13340
  31. 48400
  32. 43750
  33. 8748
  34. 1425
  35. 423
  36. 49250
  37. 15888
  38. 756
  39. 1390
  40. 20592

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