Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 436 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 50400 people. The population grows by 25% every year. What will the population be after 2 years?
2. 2.A scooter is worth ₹37500. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹49200 at 5% per year for 2 years (in ₹)?
4. 4.A scooter is worth ₹31600. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
5. 5.What amount will ₹13400 grow to in 1 year at 20% per year compound interest (in ₹)?
6. 6.Find the compound interest on ₹30300 at 12% per year for 1 year, compounded every year (in ₹).
7. 7.What amount will ₹50700 grow to in 1 year at 8% per year compound interest (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹53600 at 5% per year for 2 years (in ₹)?
9. 9.Find the compound interest on ₹10000 at 10% per year for 3 years, compounded every year (in ₹).
10. 10.Find the compound interest on ₹3300 at 5% per year for 1 year, compounded every year (in ₹).
11. 11.What is the difference between the compound interest and the simple interest on ₹8000 at 20% per year for 2 years (in ₹)?
12. 12.What amount will ₹21900 grow to in 2 years at 10% per year compound interest (in ₹)?
13. 13.Find the compound interest on ₹51800 at 10% per year for 2 years, compounded every year (in ₹).
14. 14.What is the difference between the compound interest and the simple interest on ₹17700 at 10% per year for 2 years (in ₹)?
15. 15.Find the compound interest on ₹25200 at 15% per year for 2 years, compounded every year (in ₹).
16. 16.What amount will ₹48500 grow to in 1 year at 15% per year compound interest (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹14000 at 5% per year for 2 years (in ₹)?
18. 18.A town has 46800 people. The population grows by 10% every year. What will the population be after 2 years?
19. 19.Find the compound interest on ₹9600 at 25% per year for 3 years, compounded every year (in ₹).
20. 20.A scooter is worth ₹10000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
21. 21.Find the compound interest on ₹37500 at 8% per year for 2 years, compounded every year (in ₹).
22. 22.What is the difference between the compound interest and the simple interest on ₹13700 at 20% per year for 2 years (in ₹)?
23. 23.What amount will ₹17500 grow to in 2 years at 12% per year compound interest (in ₹)?
24. 24.What is the difference between the compound interest and the simple interest on ₹5000 at 4% per year for 2 years (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹57500 at 8% per year for 2 years (in ₹)?
26. 26.Find the compound interest on ₹27200 at 25% per year for 2 years, compounded every year (in ₹).
27. 27.What is the difference between the compound interest and the simple interest on ₹2400 at 20% per year for 2 years (in ₹)?
28. 28.A scooter is worth ₹52500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
29. 29.A town has 56000 people. The population grows by 10% every year. What will the population be after 3 years?
30. 30.What is the difference between the compound interest and the simple interest on ₹23600 at 5% per year for 2 years (in ₹)?
31. 31.Find the compound interest on ₹27600 at 25% per year for 1 year, compounded every year (in ₹).
32. 32.Find the compound interest on ₹25800 at 10% per year for 1 year, compounded every year (in ₹).
33. 33.What amount will ₹10700 grow to in 1 year at 20% per year compound interest (in ₹)?
34. 34.What amount will ₹17100 grow to in 1 year at 10% per year compound interest (in ₹)?
35. 35.A town has 54200 people. The population grows by 5% every year. What will the population be after 1 year?
36. 36.A town has 11000 people. The population grows by 20% every year. What will the population be after 3 years?
37. 37.A town has 52700 people. The population grows by 25% every year. What will the population be after 1 year?
38. 38.Find the compound interest on ₹38500 at 20% per year for 3 years, compounded every year (in ₹).
39. 39.What is the difference between the compound interest and the simple interest on ₹32400 at 15% per year for 2 years (in ₹)?
40. 40.What amount will ₹2500 grow to in 2 years at 8% per year compound interest (in ₹)?

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