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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 440 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.A scooter is worth ₹15000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  2. 2.What amount will ₹24100 grow to in 2 years at 20% per year compound interest (in ₹)?
  3. 3.What is the difference between the compound interest and the simple interest on ₹53600 at 15% per year for 2 years (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹15000 at 12% per year for 2 years (in ₹)?
  5. 5.A scooter is worth ₹33000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹32600 at 10% per year for 2 years (in ₹)?
  7. 7.Find the compound interest on ₹12800 at 25% per year for 2 years, compounded every year (in ₹).
  8. 8.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
  9. 9.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
  10. 10.What amount will ₹59700 grow to in 1 year at 15% per year compound interest (in ₹)?
  11. 11.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
  12. 12.Find the compound interest on ₹56400 at 5% per year for 2 years, compounded every year (in ₹).
  13. 13.What is the difference between the compound interest and the simple interest on ₹60000 at 4% per year for 2 years (in ₹)?
  14. 14.A scooter is worth ₹46900. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  15. 15.What is the difference between the compound interest and the simple interest on ₹57500 at 12% per year for 2 years (in ₹)?
  16. 16.A scooter is worth ₹6600. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
  17. 17.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
  18. 18.What amount will ₹32000 grow to in 3 years at 20% per year compound interest (in ₹)?
  19. 19.Find the compound interest on ₹59900 at 10% per year for 2 years, compounded every year (in ₹).
  20. 20.Find the compound interest on ₹40000 at 4% per year for 2 years, compounded every year (in ₹).
  21. 21.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
  22. 22.A town has 6800 people. The population grows by 15% every year. What will the population be after 2 years?
  23. 23.What amount will ₹31500 grow to in 1 year at 10% per year compound interest (in ₹)?
  24. 24.Find the compound interest on ₹47500 at 4% per year for 2 years, compounded every year (in ₹).
  25. 25.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
  26. 26.What amount will ₹32700 grow to in 1 year at 15% per year compound interest (in ₹)?
  27. 27.What amount will ₹46800 grow to in 1 year at 20% per year compound interest (in ₹)?
  28. 28.What amount will ₹47000 grow to in 1 year at 8% per year compound interest (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
  30. 30.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
  31. 31.What amount will ₹17000 grow to in 3 years at 10% per year compound interest (in ₹)?
  32. 32.A town has 17600 people. The population grows by 25% every year. What will the population be after 1 year?
  33. 33.What is the difference between the compound interest and the simple interest on ₹46800 at 5% per year for 2 years (in ₹)?
  34. 34.A town has 42000 people. The population grows by 10% every year. What will the population be after 3 years?
  35. 35.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
  36. 36.What is the difference between the compound interest and the simple interest on ₹56800 at 25% per year for 2 years (in ₹)?
  37. 37.A scooter is worth ₹9600. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  38. 38.What is the difference between the compound interest and the simple interest on ₹45000 at 4% per year for 2 years (in ₹)?
  39. 39.A scooter is worth ₹60000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  40. 40.Find the compound interest on ₹52000 at 10% per year for 3 years, compounded every year (in ₹).

Answer key

  1. 12696
  2. 34704
  3. 1206
  4. 216
  5. 24057
  6. 326
  7. 7200
  8. 60835
  9. 9261
  10. 68655
  11. 16668
  12. 5781
  13. 96
  14. 37989
  15. 828
  16. 6072
  17. 4167
  18. 55296
  19. 12579
  20. 3264
  21. 2522
  22. 8993
  23. 34650
  24. 3876
  25. 576
  26. 37605
  27. 56160
  28. 50760
  29. 648
  30. 16
  31. 22627
  32. 22000
  33. 117
  34. 55902
  35. 8334
  36. 3550
  37. 4050
  38. 72
  39. 50784
  40. 17212

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