Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 442 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹47500 at 8% per year for 2 years (in ₹)?
3. 3.Find the compound interest on ₹25100 at 10% per year for 1 year, compounded every year (in ₹).
4. 4.What is the difference between the compound interest and the simple interest on ₹15200 at 25% per year for 2 years (in ₹)?
5. 5.What amount will ₹39400 grow to in 1 year at 12% per year compound interest (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹42000 at 5% per year for 2 years (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹15600 at 25% per year for 2 years (in ₹)?
8. 8.Find the compound interest on ₹35700 at 5% per year for 1 year, compounded every year (in ₹).
9. 9.A town has 27200 people. The population grows by 25% every year. What will the population be after 3 years?
10. 10.What is the difference between the compound interest and the simple interest on ₹57500 at 12% per year for 2 years (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹42500 at 8% per year for 2 years (in ₹)?
12. 12.What amount will ₹50000 grow to in 2 years at 5% per year compound interest (in ₹)?
13. 13.A scooter is worth ₹20800. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
14. 14.Find the compound interest on ₹24000 at 10% per year for 3 years, compounded every year (in ₹).
15. 15.Find the compound interest on ₹36200 at 15% per year for 1 year, compounded every year (in ₹).
16. 16.A town has 50800 people. The population grows by 5% every year. What will the population be after 2 years?
17. 17.What is the difference between the compound interest and the simple interest on ₹56500 at 10% per year for 2 years (in ₹)?
18. 18.What amount will ₹3200 grow to in 1 year at 4% per year compound interest (in ₹)?
19. 19.What amount will ₹34400 grow to in 1 year at 12% per year compound interest (in ₹)?
20. 20.Find the compound interest on ₹30000 at 12% per year for 2 years, compounded every year (in ₹).
21. 21.Find the compound interest on ₹4000 at 10% per year for 3 years, compounded every year (in ₹).
22. 22.What amount will ₹13700 grow to in 1 year at 10% per year compound interest (in ₹)?
23. 23.What amount will ₹56000 grow to in 3 years at 10% per year compound interest (in ₹)?
24. 24.What amount will ₹22500 grow to in 2 years at 12% per year compound interest (in ₹)?
25. 25.What amount will ₹56500 grow to in 1 year at 10% per year compound interest (in ₹)?
26. 26.A town has 49100 people. The population grows by 4% every year. What will the population be after 1 year?
27. 27.What amount will ₹37500 grow to in 2 years at 12% per year compound interest (in ₹)?
28. 28.A scooter is worth ₹48600. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹40000 at 4% per year for 2 years (in ₹)?
30. 30.Find the compound interest on ₹37300 at 10% per year for 1 year, compounded every year (in ₹).
31. 31.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
32. 32.What amount will ₹31200 grow to in 2 years at 10% per year compound interest (in ₹)?
33. 33.A town has 55000 people. The population grows by 10% every year. What will the population be after 3 years?
34. 34.A scooter is worth ₹31700. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
35. 35.What amount will ₹38000 grow to in 2 years at 20% per year compound interest (in ₹)?
36. 36.Find the compound interest on ₹38800 at 15% per year for 2 years, compounded every year (in ₹).
37. 37.Find the compound interest on ₹21400 at 10% per year for 2 years, compounded every year (in ₹).
38. 38.What amount will ₹5700 grow to in 2 years at 20% per year compound interest (in ₹)?
39. 39.Find the compound interest on ₹56000 at 25% per year for 3 years, compounded every year (in ₹).
40. 40.A scooter is worth ₹28000. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?

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